5) The height of a rocket after it is launched
For this case, what you should do is remember the kinematics expressions where we have:
a
v = a * t + vo
y = a * t ^ 2 + vo * t + i
Where,
a: acceleration
v: speed
y: vertical position
t: time
vo: initial speed
yo: initial position
We observe that the expression for the given position is given by a quadratic expression.
It is 1595. Put it on excel so you can better have an overview how it is done. You need 5 columns, column A-E. On column A, put 1 to 5 in rows 1 to 5. On column C, put the answers: 2, 7, 26, 101 and 400. On column D, put number 3 in all 5 rows. Back on column B, insert =sum(C1-A1) on row 1 and copy till row 5. On column E, insert =sum(B1+C1*D1) on row 1 and copy till row 5 and you will get 1595 at the end.
Answer:
-4 1/3
Step-by-step explanation:
26 ÷ -6
= 26 / -6 (divide both top and bottom by 2)
= 13 / 3
= -13 / 3
= -4 1/3
7×65 7×(60+5)
(7×60) (7×5)
(420)+(35)
The answer is 455
Answer:
They do not form a Pythagorean Triple.
If it was a Triple, 4^2+5^2 should equal 6^2.
4^2+5^2=16+25=41
6^2=36
41≠26
It doesn't work, therefore it is not a Pythagorean Triple.
