Answer:
What is the force of repulsion between two charges of 1c each kept 1'm apart in vacuum?
Answer. r=1/2m=50cm
Explanation:
In order to give the apple more kinetic energy than it has right now,
you must make it move faster than it is moving right now. You could
drop it, roll it, toss it, or gingerly place it in a moving car or airplane.
Whatever method you select, motion ... specifically speed ... is the
key to kinetic energy.
Answer:
No
Explanation:
The reason is when you exert the force onto any objects that stay stationary you will get a motion as the kinetic energy.
it cannot be the potential energy unless it was put at any point of heights.
Answer:
65 N
Explanation:
Assuming that the ball was at rest hence initial momentum = 0
Final momentum = mv = 1Kg × 13 ms-1 = 13 kgms-1
But
Ft= mv according to Newton's law
F= mv/t
F= 13kgms-1/0.2s
F= 65 N
Answer:
The magnitude of the net gravitational force exerted by these objects on a 42.0-kg object is 1.818 x 10⁻⁷ N
Explanation:
Given;
first object with mass, m₁ = 285 kg
second object with mass, m₂ = 585 kg
distance between the two objects, r = 4.3 m
The midpoint between the two objects = r/₂ = 4.3 /2 = 2.15 m
Gravitational force between the first object and the 42 kg object;
where;
G = 6.67 x 10⁻¹¹ Nm²kg⁻²
Gravitational force between the second object and the 42 kg object
Magnitude of net gravitational force exerted on 42kg object;
F = 3.545x 10⁻⁷ N - 1.727 x 10⁻⁷ N
F = 1.818 x 10⁻⁷ N
Therefore, the magnitude of the net gravitational force exerted by these objects on a 42.0-kg object is 1.818 x 10⁻⁷ N