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3 years ago

Drag each tile to the correct box,

Chemistry

2 answers:

juin [17]3 years ago

7 0

Number one sun, then rain, then evaporate then it starts over

Tamiku [17]3 years ago

4 0

Answer:

I hope this helped!

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PLEASE HELP PLEASE PLEASE HELP ASAP FOR PLATO!!!

photoshop1234 [79]

Answer: C-N(Longest) > C=N > CN(C triple bond N, shortest)

Explanation: Bond length is the distance between nuclei of bonded atoms.

Bond energy is the which needs to break the bond.

And bond length is always inversily proportional to bond energy.

Larger the bond energy ,shorter the bond length

4 0

3 years ago

Read 2 more answers

Calculate the volume of 0.684mol of carbon dioxide at s.t.p. show working

solong [7]

Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 0.684

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $273K$ (at STP)

$V=\frac{nRT}{P}$

$V=\frac{0.684\times 0.0821L atm/K mol\times 273K}{1atm}$

$V=15.3L$

Thus the volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

6 0

3 years ago

Magnesium reacts with hydrochloric acid (HCl) as follows. Mg(s) + 2HCl(aq) -->MgCl(2)+H(2)(g) How many milliliters of hydroge

max2010maxim [7]

We are given the number of moles of solid magnesium supplied for the reaction which is 0.02 moles while hydrochloric acid is supplied in excess thus we can say that the reaction proceeds to completion. Calculation is as follows:

0.020 mol Mg ( 1 mol H2 / 1 mol Mg ) = 0.020 mol H2 gas is produced

To convert the number of moles to volume, we use the conditions at STP of 1 mol of a substance is equal to 22.4 L. Thus,

0.020 mol H2 (22.4 L / 1 mol) (1000 mL / 1 L) = 448 mL

5 0

4 years ago

the reaction AB2C (g) <---> B2 (g) + AC (g) reached equilibrium at 900 K in a 5.00 L vessel. At equilibrium 0.0840 mol of

Verizon [17]

Answer:

k = 4,92x10⁻³

Explanation:

For the reaction:

AB₂C (g) ⇄ B₂(g) + AC(g)

The equilibrium constant, k is defined as:

$k = \frac{[B_{2}][AC]}{[AB_2C]}$ (1)

Molar concentration of the species are:

[AB₂C]: 0,0840mol / 5L = 0,0168M

[B₂]: 0,0350mol / 5L = 0,0070M

[AC]: 0,0590mol / 5L = 0,0118M

Replacing this values in (1):

$k = \frac{[0,0070][0,0118]}{[0,0168]}$

k = 4,92x10⁻³

I hope it helps!

7 0

3 years ago

What is silica sand used for?

ivann1987 [24]

Microchips I know for sure and some types of glass

6 0

4 years ago