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snow_tiger [21]
4 years ago
14

Which compound will have the larger rf value on a si02 tlc plate using 10 % ethyl acetate/ hexane as eluent: 3-decanone or 3-dec

anol, toluene or benzoic acid, cyclooctane or cyclooctanone? why?
Chemistry
1 answer:
Hatshy [7]4 years ago
7 0

The formula of determining the R_f value is:

R_f = \frac{distance travelled by the solute}{distance travelled by the solvent}

where both the distance are measured from the common origin.

10 % ethyl acetate/ hexane means it has 10 % ethyl acetate and 90 % hexane which are non-polar in nature. Hence, the non-polar compound will travel farther in the TLC plate along with the eluent and the polar compound will travel less as they remain attracted to the polar adsorbent SiO_2.

Among 3-decanone and 3-decanol, 3-decanone will have high R_f as it is non-polar.

Among toluene and benzoic acid, toluene will have high R_f as it is non-polar.

Among cyclooctane and cyclooctanone, cyclooctane will have high R_f as it is non-polar.

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Answer:

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8 0
3 years ago
Choose the aqueous solution below with the highest freezing point. These are all solutions of nonvolatile solutes and you should
GrogVix [38]

Answer:

0.200 m K3PO3

Explanation:

Let us remember that the freezing point depression is obtained from the formula;

ΔTf = Kf m i

Where;

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i = Van't Hoff factor

The  Van't Hoff factor has to do with the number of particles in solution. Let us consider the  Van't Hoff factor for each specie.

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0.200 m Ca(CIO4)2 - 3

Hence, 0.200 m K3PO3 has the greatest van't Hoff factor and consequently the greatest freezing point depression.

8 0
3 years ago
J. A gas has a volume of 12 L at 200°C with 6.0 atm.
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Gay Lussac's Law

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

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200°C = 200 + 273 = 473 K

50°C = 50 + 273 = 323 K

Input the value:

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4 0
2 years ago
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Vlad1618 [11]
I'd love to help, but you forgot to add the question.
3 0
3 years ago
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The molecular geometry of the pf3 molecule is __________, and this molecule is __________.
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4 years ago
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