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Mumz [18]
3 years ago
8

1. Sandra has a coupon to save $3 off her next

Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Answer:

the equation would be p-3$

Step-by-step explanation:

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
4 years ago
What are the solutions to the equation? x2(x+2)(x+6)=0 Enter your answers in the boxes. x = or x = or x =
Talja [164]

x^2(x+2)(x+6)=0\\\\x^2=0 \vee x+2=0 \vee x+6=0\\\\x=0 \vee x=-2 \vee x=-6

5 0
3 years ago
Read 2 more answers
Margo is creating a pencil caddy in the shape of a triangular prism. She is determining how much wood she needs to build the cad
natka813 [3]

Answer:

a little late

205 1/5 is your answer

Step-by-step explanation:

break down the 3-D figure

Find area of triangle A=1/2bh

=1/2(8 inch)(6   9/10inch)

=1/2(8 inch)(69/10 inch)

=138/5 square inch

then multiply two because you have 2 triangles

=138/5 (2)  

= 276/5 square inch

= 55 1/5 sq.in

Find area of rectangle

A = lw

=6 1/4 in (8 in)

= 25/4 (8 in.)

= 50 sq. in.

then multiply by 3 because of the three rectangles

= 50 sq. inch (3)

= 150 sq. in.

Add all together

55 1/5 sq. inch + 150 sq. inch = 205 1/5 sq. inch

4 0
3 years ago
two trapezoid together to make a hexagon what was the perimeter of the hexagon pete made. explain how you know
GaryK [48]
Cause the it the oust side has blocks you count the blocks around it and you have your answer
3 0
3 years ago
HELP THIS WAS DUE ALREADY
sergeinik [125]

Answer:

1:4

Step-by-step explanation:

Let's find the ratio of one side of Figure A to one side of Figure B. Note that the have to be the same side on each triangle (Ex: The short side and the short side or the medium length side and the medium length side or the long side and the long side)...

14:56

We can simplify this into...

1:4

4 0
2 years ago
Read 2 more answers
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