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Nutka1998 [239]
3 years ago
6

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 496g of bromine liquid is produced

. Calculate the number of moles of bromine liquid produced.
Chemistry
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

6.208 mol

Explanation:

Mass of Bromine Liquid = 496g

Number of moles = ?

Relationship between number of moles and mass is given as;

Number of moles = Mass / Molar mass

Molar mass of Bromine = 79.9g

Number of moles = 496 / 79.9 = 6.208 mol

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A 225-g sample of aluminum was heated to 125.5 oc, then placed into 500.0 g water at 22.5 oc. (the specific heat of aluminum is
Sidana [21]
when  heat gained = heat lost 

when AL is lost heat and water gain heat

∴ (M*C*ΔT)AL = (M*C*ΔT) water

when M(Al) is the mass of Al= 225g 

C(Al) is the specific heat of Al = 0.9 

ΔT(Al) = (125.5 - Tf) 

and Mw is mass of water  = 500g

Cw is the specific heat of water = 4.81 

ΔT = (Tf - 22.5) 

so by substitution:

∴225* 0.9 * ( 125.5 - Tf) = 500 * 4.81 * (Tf-22.5)

∴Tf = 30.5 °C
7 0
3 years ago
Read 2 more answers
Which is a saturated solution?
ser-zykov [4K]

Answer:

C)52g KCl in 100g water at 80°C

Explanation:

A saturated solution is one that contains as much solute as it can dissolve in the presence of excess solute at that particular temperature.

A solutibility curve is a graph that shows the variability with temperature of the solubility of a solute in a given solvent. A solutibility curve can provide information of whether a solution formed frommthe solute and solvent are saturated or not at a given temperature.

From the solubility curve in the attachment below:

A) A saturated solution of NH₄Cl will contain about 52 g solute per 100 g sat 50 °C. Thus, a solution of 40 g NH₄Cl in 100 g water at 50 °C is an unsaturated solution.

B) A saturated solution of SO₂ at 10°C will contain about 70 g of solute in 100 g of water. Thus a solution of 2g SO₂ in 100g water at 10°C is an unsaturated solution.

C) A saturated solution of KCl at 80 °C will contain about 52 g of solute in 100 g of water. Thus, a solution of 52g KCl in 100g water at 80°C is a saturated solution.

D) A saturated solution of Kl at 20 °C will contain about 145 g of solute in 100 g of water. Thus, a solution of 120g KI in 100g water at 20°C is an unsaturated solution.

7 0
3 years ago
Many appliances in your home and school use electrical energy. Which of these appliances is intended to convert electrical energ
Solnce55 [7]

Answer:

music amplifier or a loudspeaker

Explanation:

A music amplifier or a loudspeaker are a few devices that convert electrical energy into sound energy.

As it is a well known fact that energy can neither be created nor be destroyed it can only change from one form to the other. As here it is changing from electrical to sound.

6 0
3 years ago
A chef makes a marinade by mixing red pepper flakes, dried onion flakes, and a ground ginger with soy sauce. He sets the marinad
Alisiya [41]

Answer:

Suspension

Explanation:

This mixture is a simple suspension.

A suspension is a mixture of small insoluble particles of a solid in a liquid or gas. Here, it is insoluble particles in liquid.

  • Suspensions are settle on standing this is why they have to be mixed again.
  • The particles do not pass through ordinary filter paper.
  • They are usually cloudy and have an opaque color.
  • The marinade is simply a suspension.
  • It is not a solution because they do not settle on standing.
  • Also, colloids do not settle on standing.
3 0
3 years ago
Read 2 more answers
We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to
andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

  • To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of the NaOH.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of the Ca(OH)_2

We are given:

n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL  

Putting all the values in above equation, we get:

M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M

  • To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base.

We are given:

n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL

Putting values in above equation, we get:

1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M

Hence, the correct answer is Option 5.

7 0
3 years ago
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