I got 75582.
Explanation:
First, group the 40 identical candies into 20 pairs. It doesn't matter how since the candies are identical. This grouping will ensure that any assigment will contain at least two candies.
Then think of the 20 groups a 20 beads on a string. We are looking to place 11 separators between them to obtain 12 segments, each with a varying number of beads between them. How many ways are there to place 11 separators to 19 potential spaces between beads? The asnwer is 
Answer:
Mode = 19.
Median = 23.
Step-by-step explanation:
Arrange in ascending order:
8 9 12 15 17 18 19 19 20 22 24 25 26 27 28 31 34 36 40 43
The modal amount is the one which occurs most , which is 19.
The median is the middle value of the 20 amounts.
As there is an even number of amounts the median is the mean of the 2 middle numbers:
Median = (22 + 24) / 2
= 23.
I can help you understand this, however there is nothing but 'M'
F=95(K−273.15)+32
Switch the equation so that F is on the right side:
95(K−273.15)+32 = F
Use the distributive property:
95K + 95(-273.15) + 32 = F
95K - 25949.25 + 32 = F
95K - 25917.25 = F
Add 25917.25 to both sides:
95K = 25917.25 + F
Divide each term by 95:
K = 25917.25 / 95 + F/95
K = (25917.25 + F) /95
