I will give brainliest to whoever gets them both right! Needed ASAP (5 and 6)
1 answer:
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Part A:
Look at the image attached to my answer for the graph of the inequalities.
There are two different lines provided, one with a more negative slope than the other. The shaded area between them represents the solution set.
The green line is 2x+y≤8, the blue line is x+y≥4
Part B:
To test if (8, 10) is included, substitute x = 8 and y = 10 into both inequalities. If it doesn't satisfy one of them, then it isn't included in the solution area.
2(8) + 10 ≤ 8
16 + 10 ≤ 8
26 ≤ 8... 26 is NOT less then or equal to 8
Thus, (8, 10) cannot be a solution since the inequality is not true.
Part C:
I'm going to choose a random point from the graph, (2, 3). For your answer, any point in the shaded region where both x and y is positive will work.
The point (2, 3) means that Sarah can buy 2 cupcakes and 3 pieces of fudge to get at least 4 pastries for her siblings while staying within her 8 dollar budget.
Let me know if you need any clarifications. Happy Studying~
