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Vika [28.1K]
2 years ago
7

Alguien me puede ayudar con esa tabla ​

Physics
1 answer:
Scilla [17]2 years ago
7 0
私は英語がわかりません sorry pls translate
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The ____ is the place where position equals zero
Alexus [3.1K]
The answer to your question is the Origin 
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3 years ago
It takes 1 minute for 45 c to pass a point in a circuit, what is the current flowing through the circuit?
ohaa [14]

Answer:

0.75 A

Explanation:

An electric current is a flow of charged particles.

A current is defined through its intensity, which is given by:

I=\frac{q}{t}

where

I is the current intensity

q is the charge passing through a given point in the circuit

t is the time it takes for the charge q to pass that point in the circuit

In this problem, we have:

q = 45 C is the charge passing through the point in the circuit

t=1 min = 60 s is the time elapsed

Therefore, the current intensity is:

I=\frac{45}{60}=0.75 A

5 0
3 years ago
What kind of water that most used in industrial
ValentinkaMS [17]

<em>Hard </em><em>water </em><em>is </em><em>mostly </em><em>used </em><em>in </em><em>Industries </em>

3 0
3 years ago
A woman can see clearly with her right eye only when objects are between 45 cm and 155 cm away. Prescription bifocals should hav
Yuri [45]

Answer:

Explanation:

given,

A woman can see object between 45 cm and 155 cm

glasses is 2 cm from the eye

to able to read a book distance = 25 cm

For the  object distant apart

\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}

\dfrac{1}{f}= \dfrac{1}{\infty}+\dfrac{1}{-153}

\dfrac{1}{f} = - 6.53 \times 10^{-3}

hence, D = - 0.653  m

For the object at the near point

\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}

\dfrac{1}{f}= \dfrac{1}{23} +\dfrac{1}{-43}

\dfrac{1}{f}= 0.0202 cm

hence, D = 2.02 m

8 0
3 years ago
A spring with a spring constant of 45 N/m is pulled 1.4 m away from its equilibrium position. How much potential energy is store
Luda [366]

Elastic potential energy is given by:

E =\dfrac{1}{2}kx^2

Where k is the spring constant in N/m and x is displacement from equilibrium position in m. Evaluating:

E =\dfrac{1}{2}kx^2 = \dfrac{1}{2}(45\;N/m)(1.4\;m)^2 = 44.1\;J

A/ The potential energy is stored in the spring is 44.1 J.

7 0
3 years ago
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