Yes that is correct. We know this because 4.00 x 10 4 Pa is constant. If you have 2.00×10−3m3 then you do the following: (2.00×10^−3)(4.00×10^<span> 4) = </span>8.00×10^−3. That is how you get your answer
Answer:
Take-off velocity = v = 81.39[m/s]
Explanation:
We can calculate the takeoff speed easily, using the following kinematic equation.

where:
a = acceleration = 4[m/s^2]
x = distance = 750[m]
vi = initial velocity = 25 [m/s]
vf = final velocity
![v_{f}=\sqrt{(25)^{2}+(2*4*750) } \\v_{f}=81.39[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3D%5Csqrt%7B%2825%29%5E%7B2%7D%2B%282%2A4%2A750%29%20%7D%20%5C%5Cv_%7Bf%7D%3D81.39%5Bm%2Fs%5D)
Answer:
We conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.
Hence, option D is correct.
Explanation:
Given
To determine
Mass m = ?
Important Tip:
-
The mass of a rock can be found using the formula F = ma
Using the formula

where
- a is the acceleration (m/s²)
now substituting F = 500, and a = 75 m/s² in the formula


switch sides

Divide both sides by 75

simplify

kg
Therefore, we conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.
Hence, option D is correct.
20 electrons and 2 valence electrons
There is no difference. 5 is the same as 5.0