Answer:
distance and time
Explanation: the farther you go and how much time it will take you
Answer:
1.199km/h towards west
2.17km/h towards upstream direction
3.702km/h towards east
4.2km/h towards downstream direction
5.a.149km/h towards east
b.1043km
Explanation:
1.V p,e = Vp,w + Vw,e
= 211km/h-12km/h
=199km/h towards west
2. Vb,o=Vb,r+Vr,o
Vb,o=22-5km/h
=17km/h towards upstream direction
3.Vj,w= Vj,e + Ve,w
Vj,w = 740-38km/h
= 702km/h towards east
4.Vk,r= Vk,e+ Ve,r
Vk,r=33 - 31km/h
=2km/h towards downstream direction
5.a.Vp,e=Vp,w +Vw,e
Vp,e=216-67km/h
=149km/h towards east
b. distance =speed * time
= 149km/h * 7h
=1043km
[V p,e-velocity of plane relative to earth(ground)]
[p-plane ,w-wind ,e-earth, b-boat, r-river, o-object, j-jet, k-kayaker,]
Answer:
Explanation:
Diffraction is observed when a wave is distorted by an obstacle whose dimensions are comparable to the wavelength. The simplest case corresponds to the Fraunhofer diffraction, in which the obstacle is a long, narrow slit, so we can ignore the effects of extremes.
This is a simple case, in which we can use the Fraunhofer single slit diffraction equation:
Where:
Solving for λ:
Replacing the data provided by the problem:
We can approach this in another way.
We know that sin(∅) = height / hypotenuse.
Thus, for x, height is 1 and hypotenuse is 3. Using Pythagoras theorem,
3² = 1² + b²
b = √8
cos(x) = b/hypotenuse
cos(x) = √8 / 3
Now, lets consider y:
sec(y) = 1 / cos(y) = 1 / base / hypotenuse = hypotenuse / base
The hypotenuse is 25 and the base is 24. We again apply Pythagoras theorem to find the third side, which works out to be:
height = 7
sin(y) = height / hypotenuse
sin(y) = 7/25
Now, sin(x + y) =
sin(x)cos(y) + sin(y)cos(x)
= (1/3)(24/25) + (√8 / 3)(7/25)
= 8/25 + 7√8/75
= (24 + 14√2) / 75
Answer:
The minimum speed when she leave the ground is 6.10 m/s.
Explanation:
Given that,
Horizontal velocity = 1.4 m/s
Height = 1.8 m
We need to calculate the minimum speed must she leave the ground
Using conservation of energy
Put the value into the formula
Hence, The minimum speed when she leave the ground is 6.10 m/s.