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andrew-mc [135]
3 years ago
8

A force of 6.0 Newtons is applied to a block at rest on a horizontal frictionless surface over a 7.0 meter span. How much energy

is gained by the block?
a) 3.0 m/s

b) 7.0 m

c) 42 J

d) 6.0 N
Physics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

C. 42J

Explanation:

Given data

Force= 6N

Distance= 7m

Required

The energy gained

Work= Force* Distance

Work= 6*7

Work= 42Joules

Hence the option c 42J is correct

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A 50 kg archer standing on frictionless ice shoots a 100g arrow at a speed of 100 m/s what uis the recoild pseed of the archer?
nexus9112 [7]

Answer:

v= 0.2 m/s

Explanation:

Given that

m₁ = 50 kg

m₂ = 100 g = 0.1 kg

u =10 0 m/s

If there is no any external force on the system  then the total linear momentum of the system will be conserve.

Initial linear momentum = Final momentum

m₁u₁ + m₂ u₂ =m₂ v₂ +m₁v₁

50 x 0 + 0.1 x 100 = 50 v + 0

0+ 10 = 50 v

v=\dfrac{10}{50}\ m/s

v= 0.2 m/s

Therefore the recoil speed will be 0.2 m/s.

7 0
3 years ago
Does earths Roation causes gravity?​
gogolik [260]

Answer:

he gravity of Earth, denoted by g, is the net acceleration that is imparted to objects due to the combined effect of gravitation (from mass distribution within Earth) and the centrifugal force (from the Earth's rotation )

8 0
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The sun produces energy by forming in its core
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7 0
3 years ago
You are making a circular turn in your car on a horizontal road when you hit a big patch of ice, causing the force of friction b
adell [148]

Answer:

c

Explanation:

The car travels with centripetal acceleration which is directed to the center of the circle but the velocity is changing since the car faces different direction as it travels in the circular direction. When the friction is zero between the tires of the car and the road, it will continue in the direction of its tangential velocity which will be along a straight-line path in its original direction.

4 0
3 years ago
An air-gap, parallel plate capacitor with area A and gap width d is connected to a battery that maintains the plates at potentia
sergejj [24]

Answer:

The new potential energy decreases by the factor of 2 to the old potential energy.

Explanation:

Capacitance of a parallel plate capacitor is given by the relation :

C = (ε₀A)/d

Here ε₀ is vacuum permittivity, A is area of the capacitor plate and d is the distance between them.

Potential energy of the capacitor, U = \frac{1}{2}CV^{2}

Here V is the potential difference between the plates.

According to the problem, the distance between the plates get double but area remains same. So,

d₁ = 2d

Here d₁ is new distance between the plates.

Hence, new capacitance is :

C₁ = (ε₀A)/d₁ = (ε₀A)/2d = C/2

The capacitor have same potential difference that is V. Hence, the new potential energy is :

U₁ = \frac{1}{2}C_{1} V^{2} = \frac{1}{2}\frac{C}{2} V^{2}

U₁ = U/2

\frac{U_{1} }{U} = \frac{1}{2}

7 0
3 years ago
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