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andrew-mc [135]
3 years ago
8

A force of 6.0 Newtons is applied to a block at rest on a horizontal frictionless surface over a 7.0 meter span. How much energy

is gained by the block?
a) 3.0 m/s

b) 7.0 m

c) 42 J

d) 6.0 N
Physics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

C. 42J

Explanation:

Given data

Force= 6N

Distance= 7m

Required

The energy gained

Work= Force* Distance

Work= 6*7

Work= 42Joules

Hence the option c 42J is correct

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JOSEPH JOGS FROM END A TO OTHER END B OF A straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back
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(a) The average speed from A to B would be 1.76 metre per second and the average velocity from A to B would also be 1.76 metre per second 

<span>(b) The average speed from A to C would be 1.73 metre per second and the average velocity from A to C would be 0.87 metre per second</span>
3 0
3 years ago
What two types of scientific knowledge can be expressed as mathematical equations? (Please don't tell me the answer could you pl
gtnhenbr [62]
An example would be 2 types of motion. It could be rectilinear or projectile motion. There are various equations for each type. Since you don't want me to tell you the answer, I could just express it in words. Then, it will be up to you to translate into mathematical equations.

For rectilinear motion, the distance traveled is equal to the initial velocity times the time, plus one-half of the acceleration times the square of the time. For projectile motion, the maximum distance is equal to the square of the initial velocity multiplied with the square of the sine of the launch angle, all over twice the gravity.
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On a hot day, warm air on land rises and collides with cool air. Which of these weather conditions is most likely to follow?
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I think its......C. Hurricane

3 0
3 years ago
Read 2 more answers
Let's examine over the next few questions an NFL kick as described in the 3rd Law video. The announcer claimed that the ball is
hichkok12 [17]

Answer:

8451.62109367671 Newtons

Explanation:

1\ kg=1\times 9.8066500286389=9.8066500286389\ N

1 \lb=2.2046226218488\ kg

It is known that

1\ lbs=\dfrac{9.8066500286389}{2.2046226218488}=4.4482216282508\ N

So,

1900\ lbs=1900\times 4.4482216282508\\\Rightarrow 1900\ lbs=8451.6210936765\ N

The force in Newtons is 8451.6210936765 Newtons

4 0
3 years ago
Suppose a grower sprays (2.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water
Bond [772]

There is no temperature change which drives heat flow, thus no heat will be released by the water.

<h3>Heat released by the water when it freezes</h3>

The heat released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

  • m is mass of water
  • c is specific heat capacity of water
  • ΔФ is change in temperature = Фf - Фi

Initial temperature of water, Фi = 0 °C

when water freezes, the final temperature, Фf = 0 °C

Q = 22 x 4200 x (0 - 0)

Q = 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

Learn more about heat flow here: brainly.com/question/14437874

6 0
2 years ago
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