To solve the question you use the following formula:
concentration (1) × volume (1) = concentration (1) × volume (1)
3 M × volume (1) = 1.8 M × 50 mL
volume (1) = (1.8 M × 50 mL) / 3 M = 30 mL
Answer:
The concentration of nitrate ion 
is 0.033 M.
Explanation:
1 mole of ![[Al^{3+}]](https://tex.z-dn.net/?f=%5BAl%5E%7B3%2B%7D%5D)
= 3 mole
Let ![[NO_{3}^{-}]](https://tex.z-dn.net/?f=%5BNO_%7B3%7D%5E%7B-%7D%5D)
= 3y
then according to above reaction,
= y
= 0.10 M (given)
= ?
3y = 0.10 M
y = 0.033 M
So ,concentration of = y = 0.033 M
Answer:
The final pressure of gas is 82.64 KNm⁻²
Explanation:
Given data:
Initial volume of gas = 180 cm³
Temperature of gas = 27°C
Initial pressure = 101 KNm⁻²
Final volume = 220 cm³
Final pressure = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
101 KNm⁻² × 180 cm³ = P₂
× 220 cm³
P₂ = 18180 KNm⁻². cm³/220 cm³
P₂ = 82.64 KNm⁻²
The final pressure of gas is 82.64 KNm⁻².
Mass of chlorine = 
(given)
Molar mass of chlorine =
Now, number of moles is defined as the ratio of given mass in gram to the molar mass of the compound.
Number of moles = 
Number of moles of chlorine =
= 
Now, according to significant figure rules, the least number of significant figure in the question identifies the number of significant figures in the solution.
Thus, in question, both digit have four significant figures, therefore, the answer must be in four significant figures.
Hence, number of moles of chlorine = 
