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Advocard [28]
3 years ago
5

The pictures shows what a student observed when he looked through a hand lens at a penny.

Physics
2 answers:
igomit [66]3 years ago
7 0
The answer is A. Refracted
sergeinik [125]3 years ago
6 0
A. The light is refracted
You might be interested in
Suppose your hair grows at the rate of 1/55 inch per day. Find the rate at which it grows in nanometers per second. Because the
qwelly [4]

Answer:5.35nm

Explanation:

Consider that 1 inch is = 0.0254m

we have,

1m= 1x10^9 nm  

While:

0.0254m = 2.54x10^7nm  

1/55 (2.54x10^7) = 4.6181 x 10^5nm  

1 day= 24 hrs  

= (24x60) when calculating in min  

= (24x60x60) calculating in seconds we have:

= 8.64x10⁴sec  

In 8.64x10^4 seconds, the hair grows by 4.6181 x 10^5nm

Therefore, the amount by which the hair grows in 1 second  will be;

= (4.6181 x 10^5)/(8.64x10^4)  

= 5.35nm  

The rate of growth will be 5.35nm

7 0
3 years ago
The most distal part of a nail is called the ____________ . The most proximal part of the nail that is embedded in the skin is t
ankoles [38]

Answer:

1.Free edge

2.Nail Root

3.Nail matrix

4.lunula

Note: The numbering coincides respectively with the dashes in the questions.

Explanation:

Free edge is the distal white nail ending.

Nail Root is the proximal part of the nail embedded in the skin.

Nail matrix is the actively growing part of the nail were the nail root thickens

Lunula the whitish semilunar area of the proximal end of the nail body it appears whitish because stratum basala obscures. the underlying blood vessels.

7 0
3 years ago
A pitot tube indicates a pressure of 155 kPa when placed in an air stream in which the temperature is 15°C and the Mach number i
mel-nik [20]

To solve this problem we will start by defining the relationship of the pitot tube and the value indicated in the pressure. We will take advantage of this relationship to obtain a ratio between the defined pressures and proceed to calculate the total and static pressure of the system through the correlation of pressure in isotropic systems. Finally we will perform this same procedure for pressure. Pitot tube measure the total pressure minus static pressure, then

p_0 - p = 155kPa

\frac{p_0}{p} -1 = \frac{155}{p}

\frac{p_0}{p} = \frac{155}{p} +1

Express the total pressure and static pressure ratio

\frac{p_0}{p} = [1+\frac{\gamma-1}{2}M^2]^{\frac{\gamma}{\gamma-1}}

\frac{155}{p} +1 = [1+\frac{1.4-1}{2}(0.7)^2]^{\frac{1.4}{1.4-1}}

\frac{155}{p} +1=1.3871

p = 400.4kPa

Hence the static pressure is 400.4kPa

Express stagnation to static temperature ratio,

\frac{T_0}{T} = 1+\frac{\gamma-1}{2}M^2

\frac{T_0}{(15+273)K} = 1+\frac{1.4-1}{2}(0.7)^2

T_0 = 316.224K

Therefore the stagnation temperature is 316.224K

5 0
3 years ago
Anne lifts a 9.0 kg barbell with an upward force of 120 N. What is the magnitude of the acceleration of the barbell while Anne i
melamori03 [73]

Answer:

<h2>13.33 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{120}{9}  \\  = 13.3333333...

We have the final answer as

<h3>13.33 m/s²</h3>

Hope this helps you

5 0
3 years ago
Write scientific name of pea​
Scrat [10]
Pisum sativum is the answer
6 0
3 years ago
Read 2 more answers
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