Answer:
A silicone atom shares an electron pair with each oxygen atom
Explanation:
Because the silicone dioxide molecule has one silicone atom:two oxygen atoms....
Hence...since silicone has four electrons in the outter shell..which are used for bonding...each oxygen atom shares two electrons(an electron pair) with the silicone atom...so as to fill the outter shell of the oxygen atom
<span>equilibrium constant times the concentration of water. - 100% guaranteed correct</span>
Ideal gas law: PV = nRT
P-pressure
V-volume
n-number of moles(m/M)
R-constant
T- temperature
State given info:
V=10L
T=298k
P=203kPa
R=8.31(only for kPa, for pressure at atm use 0.08206)
Sub in:
(203kPa)(10L)=n(8.31)(298)
Rearrange:
n= (203)(10) / (8.31)(298)
n = 0.819745mol in gas sample
Answer:
92.4 grams.
Explanation:
- From the balanced reaction:
<em>CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,</em>
1.0 mole of CaCO₃ reacts with 2.0 moles of HCl to produce 1.0 mole of CaCl₂, 1.0 mole of CO₂, and 1.0 mole of H₂O.
- We need to calculate the no. of moles of (104 g) of CaCO₃:
<em>no. of moles of CaCO₃ = mass/molar mass</em> = (104 g)/(100.08 g/mol) = <em>1.039 mol.</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CaCO₃ produce → 1.0 mole of CaCl₂.
∴ 1.039 mole of CaCO₃ produce → 1.039 mole of CaCl₂.
∴ The amount of CaCl₂ produced = no. of moles x molar mass = (1.039 mol)(110.98 g/mol) = 114.3 g.
∵ percent yield of the reaction = [(actual yield)/(theoretical yield)] x 100.
Percent yield of the reaction = 80.15%, theoretical yield = 115.3 g.
<em>∴ actual yield = [(percent yield of the reaction)(theoretical yield)]/100 </em>= [(80.15%)/(115.3 g)] / 100 = <em>92.42 g ≅ 92.4 g.</em>
<span>crushing a can
</span><span>chopping wood
</span>shredding paper
