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nydimaria [60]
3 years ago
6

What is PO3 compound name?

Chemistry
1 answer:
OleMash [197]3 years ago
4 0

Answer:

PHOSPHITE ION is the correct answer.

Explanation:

Hope this helped Mark BRAINLIEST!!!

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Food in the stomach is broken down by powerful acids and turned into?
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<span>In this particular item, we are to determine how we call the acidic fluid-like substance that is formed after the food in the stomach is broken down by a powerful acid. The answer to this question is CHYME. The powerful acid that is referred in this item is more specifically gastric juices. </span>
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3 years ago
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It takes Mark two hours to ride his bike 12 miles to his grandma’s house. What is Mark’s speed in miles per hour? I need an answ
lions [1.4K]

Answer:

Mark has a speed of 6 MPS (Miles Per Hour)

Explanation:

It took mark 2 hours to ride his bike to his grandma's house, which was 12 miles away. I divided 2 by 12 and got 6. Remember this: mph = miles away ÷ time.

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2 years ago
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Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

7 0
3 years ago
What is the percent composition by mass of sulfur in the compound mgso4
Margaret [11]

Answer:

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.

Explanation:

Molar mass of compound = 120 g/mol

Number of sulfur atom = 1

Atomic mass of sulfur = 32 g/mol

Percentage of element in compound :

=\frac{\text{Number of atoms}\times \text{Atomic mass}}{\text{molar mas of compound}}\times 100

Sulfur :

=\frac{1\times 32 g/mol}{120 g/mol}\times 100=26.7\%

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.

6 0
3 years ago
Please answer this thanks!!...
Alex17521 [72]

Answer:sorry.

Explanation:

4 0
3 years ago
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