Answer:
All are true except the last point that says that a battery is a current source and the current at the outlet is always the same.
Explanation:
- A battery is an electro-chemical device which converts the chemical energy into usable electrical energy thus it provides electrical energy.
- Since, the battery maintains a a constant potential difference between its terminals, once connected.
- Since, the movement of electric current requires energy, which is supplied by the electric potential energy stored in the battery.
- The current in the battery flows as per the Ohm's law and we can not say that the current leaving will always remain constant.
- As the current is the flow of electric charge, and charges are not stored in batteries unlike capacitors, thus the current at the leaving end will depend on Ohm's law and will vary accordingly.
Answer:
v1=21.81m/s
Explanation:
<em>When a golfer tees off, the head of her golf club, which has a mass of 160 g, is traveling 50 m/s just before it strikes a 46 g golf ball at rest on a tee. Immediately after the collision, the club head continues to travel in the same direction but at a reduced speed of 44 m/s. Neglect the mass of the club handle and determine the speed (in m/s) of the golf ball just after impact.</em>
According to the law of conservation of momentum, if the net external force on a system is zero, then the linear momentum of the system is conserved.
During collision of two particles, the external force on the system of two colliding particles is zero (only internal force acts between the colliding particles), therefore, the momentum is conserved during the collision.
Answer and Explanation:
Given :
head of the golf club=160g
velocity of the golf club=50 m/s
golf ball mass=46g
velocity=om/s
m1u1+m2u2=m1v1+m2v2.........................................1
160*50 +46*0=160*44+46*v1
8000=7040+46v1
960=46v1
v1=960/46
v1=21.81m/s
Answer:
0.240 J/g/°C
Explanation:
q = mCΔT
47.3 cal = (55.00 g) C (15.0°C)
C = 0.0573 cal/g/°C
Usually, specific heat is measured in J/g/°C, so we can convert:
C = 0.0573 cal/g/°C × 4.184 J/cal
C = 0.240 J/g/°C
