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djyliett [7]
3 years ago
11

How can the solar wind affect life on earth​

Physics
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

Explanation:

If the material carried by the solar wind reached a planet's surface, its radiation would do severe damage to all life that exists on earth.

Thankfully that won't happen because Earth's magnetic field serves as a shield, redirecting the material around the planet so that it streams beyond it.

HOPE THIS HELPED!!!

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Which part of the electromagnetic spectrum is nearest to radio waves?
svetlana [45]

The part of the electromagnetic spectrum closest to radio waves is <u> microwaves</u>.

The wavelength of radio waves ranges from 10 cm to more than 1 km. The part of the electromagnetic spectrum that occurs closest to the radio waves is called the microwave region.

Microwaves have wavelengths ranging from around 1 mm to 10 cm.

The waves overlap in the region of 10 cm.

Thus, the region of electromagnetic spectrum closest to radiowaves is <u> microwaves.</u>

3 0
3 years ago
Read 2 more answers
Write the formula of mechanical advantage​
Zanzabum

Answer:

the formula of mechanical advantage is

MA = load / effort

VR = effort distance / load distance

hope it is helpful to you

7 0
3 years ago
If two metal balls each have a charge of -10^-6 C and the repulsive force between them is 1 N, how far apart are they? (Coulomb'
Vitek1552 [10]

Answer:

The distance between the charges is 9.5 cm

(c) is correct option

Explanation:

Given that,

Charge q= 10^{-6}\ C

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

F = \dfrac{kq_{1}q_{2}}{r^2}

Where, q = charge

r = distance

F = force

Put the value into the formula

1=\dfrac{9.0\times10^{9}\times(-10^{-6})^2}{r^2}

r=\sqrt{9\times10^{9}\times(-10^{-6})^2}

r=0.095\ m

r= 9.5\ cm

Hence, The distance between the charges is 9.5 cm

4 0
3 years ago
The biological roles of complex organic molecules are determined by their shape -- the way atoms and electrons create charge dis
Hatshy [7]

Answer:

a) P_α =  exp (-ΔE / kT),  b)   P_β = 0.145 , d)  ΔE = 309.7 meV

Explanation:

The expression for the number of molecules or particles in a given state in Boltzmann's expression

            n = n₀ exp (-ΔE / kT)

Where k is the Bolztmann constant and T the absolute temperature

The probability is defined as the number of molecules in a given state over the total number of particles

          P = n / n₀ = exp (- ΔE / kT)

Let's apply this expression to our case

a) P_α = n_α / n₀ = exp (-ΔE / kT)

b) the Boltzmann constant

       k = 1,381 10⁻²³ J / K (1 eV / 1.6 10⁻¹⁹ J) = 8.63 10⁻⁵ eV / K

       kT = 8.63 105 300 = 2,589 10⁻² eV

       P_β = exp (- 50 10⁻³ /2.589 10⁻² = exp (-1.931)

       P_β = 0.145

c) If the temperature approaches absolute zero, the so-called is very high, so there is no energy to reach the excited state, therefore or all the molecules go to the alpha state

d) For molecules to spend ¼ of the time in this beta there must be ¼ of molecules in this state since the decay is constant.

        P_β = ¼ = 0.25

     

       P_β = exp (- ΔE / kT)

       ΔE = -kT ln P_β

       ΔE = - 2,589 10⁻² ln 0.25

       ΔE = 0.3097 eV

       ΔE = 309.7 meV

3 0
3 years ago
Would an increase in pressure favor the formation of ozone or of oxygen?
max2010maxim [7]
<h3><u>Answer;</u></h3>

<u>An increase in pressure favors the formation of ozone </u>

<h3><u>Explanation;</u></h3>
  • Ozone, O3, decomposes to molecular oxygen in the stratosphere according to the reaction

2O3(g) ⇆ 3O2 (g).

  • There are more moles of product gas than moles of reactant gas. An increase in total pressure increases the partial pressure of each gas, shifting the equilibrium towards the reactants.
  • Therefore; an increase in pressure favors backward reactions towards the formation of ozone.
8 0
3 years ago
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