Answer:
K = .3941 × 10³ W/m.K
Explanation:
Qcond = K A ΔT÷ L
∴K = Qcond ×L ÷ A ΔT
J ÷ S = P
P = I × V =Qcond
∴Qcond = I × V
= 0.6 A × 110 V
=66 W
L = 0.12 m
ΔT = 8 °C
Qcond =33 V
Area = (πD²) ÷ 4
= [π (4 × 10⁻² )²] ÷ 4
= 1.256 × 10⁻³ m²
∴A = 1.256 × 10 ⁻³³ m²
So K = ( Qcond × L ) ÷ A ΔT
= (33) (0.12 ) ÷ (1.256 ×10⁻³ ) × 8
= 0.3941 × 10³ W/m .K
Probability of it being a boy is 17/25 which is .68
The total positive charge on a copper penny is <u>1.36×10⁵C.</u>
One gram molecular weight of an element contains Avogadro number of independent entities. The atomic weight of Copper is 63.546.
Therefore 63.546 g of Copper contains 6.023×10²³atoms of copper.Calculate the number of atoms N in 3.1 g of copper in the penny.
The atomic number Z of copper is 29. Atomic number is equal to the number of protons present in the nucleus of the atom. Thus, a copper atom has 29 protons. Each proton has a charge e equal to 1.6×10⁻¹⁹C.
Therefore the total charge Q on the penny is given by,
Substitute 2.938×10²²for N, 29 for Z and 1.6×10⁻¹⁹C for e.
The total positive charge on a copper penny is <u>1.36×10⁵C.</u>
Answer:
h = 1/2gt^2
Is the formula for the height of a free falling object.
Put in the numbers:
h = 1/2*9.8 (gravitational constant) * 10^2
h=490 meters.
Please note that the gravitational constant is approximate, you could also use a more specific value or 10
Answer:
One second is defined by taking the fixed numerical value of the caesium frequency ∆ν, the unperturbed ground-state hyperfine transition frequency of the caesium 133 atom, to be 9 192 631 770 (9.192631770 x 10⁹ ) cycles of the radiation, when expressed in the unit Hz, which is equal to s−¹.
One second is equal to 1/86,400 of a mean solar day.