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3 years ago

Which part of the electromagnetic spectrum is nearest to radio waves?

2 answers:

6 0

i think that the part of electromagnetic spectrum closest to the radio wave in the microwave. on the spectrum the microwaves wavelength is ranged from 1mm to about 10cm.

svetlana [45]3 years ago

3 0

The part of the electromagnetic spectrum closest to radio waves is <u> microwaves</u>.

The wavelength of radio waves ranges from 10 cm to more than 1 km. The part of the electromagnetic spectrum that occurs closest to the radio waves is called the microwave region.

Microwaves have wavelengths ranging from around 1 mm to 10 cm.

The waves overlap in the region of 10 cm.

Thus, the region of electromagnetic spectrum closest to radiowaves is <u> microwaves.</u>

You might be interested in

To obtain the same resistance force, a greater force must be exerted in a machine of lower efficiency than in a machine

Sindrei [870]

Answer: True.

Explanation:

A resistance force is also known as friction. And the efficiency of a machine is affected by friction.

A machine of lower efficiency has higher magnitude of friction than a machine of higher efficiency.

Therefore, To obtain the same resistance force, a greater force must be exerted in a machine of lower efficiency than in a machine of higher efficiency. This is true

7 0

3 years ago

If an object has a mass of 20 grams and a volume of 40 cm3, what is its density in g/cm3?

sattari [20]

Density = Mass/Volume
So, given mass = 20 g and volume = 40 cm^3
By substituting in above equation, Density = 20/40 = 0.5 g/cm^3
Hope it helps.

3 0

4 years ago

In unit-vector notation, what is the torque about the origin on a particle located at coordinates (0 m, −3.0 m, 2.0 m) due to fo

irinina [24]

Answer:

The torque about the origin is $2.0Nm\hat{i}-8.0Nm\hat{j}-12.0Nm\hat{k}$

Explanation:

Torque $\overrightarrow{\tau}$ is the cross product between force $\overrightarrow{F}$ and vector position $\overrightarrow{r}$ respect a fixed point (in our case the origin):

$\overrightarrow{\tau}=\overrightarrow{r}\times\overrightarrow{F}$

There are multiple ways to calculate a cross product but we're going to use most common method, finding the determinant of the matrix:

$\overrightarrow{r}\times\overrightarrow{F} =-\left[\begin{array}{ccc} \hat{i} & \hat{j} & \hat{k}\\ F1_{x} & F1_{y} & F1_{z}\\ r_{x} & r_{y} & r_{z}\end{array}\right]$

$\overrightarrow{r}\times\overrightarrow{F} =-((F1_{y}r_{z}-F1_{z}r_{y})\hat{i}-(F1_{x}r_{z}-F1_{z}r_{x})\hat{j}+(F1_{x}r_{y}-F1_{y}r_{x})\hat{k})$

$\overrightarrow{r}\times\overrightarrow{F} =-((0(2.0m)-0(-3.0m))\hat{i}-((4.0N)(2.0m)-(0)(0))\hat{j}+((4.0N)(-3.0m)-0(0))\hat{k})$

$\overrightarrow{r}\times\overrightarrow{F}=-2.0Nm\hat{i}+8.0Nm\hat{j}+12.0Nm\hat{k}=\overrightarrow{\tau}$

4 0

3 years ago

2. 3000. kg car is moving across level ground at 5.0 m/s when it begins an

gizmo_the_mogwai [7]

Answer:

yes

Explanation: Work is done when there is movement. Therefore it was work was being done.

7 0

3 years ago

A bus traveling at 25.2mi/h speeds up at a constant rate of 9.2x10^-3 m/s^2. What velocity does it reach 25min later?

Softa [21]

Answer: actually to solve this u must know what 3.2m/s2 is..do u know it ??...wel let me tell...3.2m/s2 means that in every second the speed of the body increases by 3.2m/s..so if it acts for 6.8 seconds..increase in speed will be 3.2*6.8 however note that this is the increase in speed.. have to change this in km/hr & add this to the initial speed(27km/hr) to get the answer....hope this has cleared ur doubts....

Explanation:

6 0

3 years ago