All categories

3 years ago

Which part of the electromagnetic spectrum is nearest to radio waves?

2 answers:

6 0

i think that the part of electromagnetic spectrum closest to the radio wave in the microwave. on the spectrum the microwaves wavelength is ranged from 1mm to about 10cm.

svetlana [45]3 years ago

3 0

The part of the electromagnetic spectrum closest to radio waves is <u> microwaves</u>.

The wavelength of radio waves ranges from 10 cm to more than 1 km. The part of the electromagnetic spectrum that occurs closest to the radio waves is called the microwave region.

Microwaves have wavelengths ranging from around 1 mm to 10 cm.

The waves overlap in the region of 10 cm.

Thus, the region of electromagnetic spectrum closest to radiowaves is <u> microwaves.</u>

You might be interested in

How much heat is required to evaporate 0.15 kg of lead at 1750°C, the boiling point for lead? The heat of vaporization for lead

lara [203]

Answer:

Heat required = mass× latent heat Q = 0.15 × 871 ×

3 0

3 years ago

PLEASE HELP ME TIMED TEST!!!

malfutka [58]

Answer:

Explanation:

I just want the points to be completely honest with you.

7 0

2 years ago

Read 2 more answers

A particle moves along a straight path through a displacement d = 2.5i + cj while a force F = 8.5i + -8.5j acts on it. The displ

Zanzabum

Answer:

Explanation:

Work is defined as the scalar product of force and distance

W=F•d

Given that

F = 8.5i + -8.5j. +×-=-

F=8.5i-8.5j

d = 2.5i + cj

If the work in the practice is zero, then W=0

therefore,

W=F•ds

0=F•ds

0=(8.5i -8.5j)•(2.5i + cj)

Note that

i.i=j.j=k.k=1

i.j=j.i=k.i=i.k=j.k=k.j=0

So applying this

0=(8.5i -8.5j)•(2.5i + cj)

0= (8.5×2.5i.i + 8.5×ci.j -8.5×2.5j.i-8.5×cj.j)

0=21.25-8.5c

Therefore,

8.5c=21.25

c=21.25/8.5

c=2.5

7 0

3 years ago

Three point charges, two positive and one negative, each having a magnitude of 20 C are placed at the vertices of an equilateral

Daniel [21]

The resultant force on the positive charge is mathematically given as

X=40N

<h3>What is the magnitude of the electrostatic force on the negative charge?</h3>

Question Parameters:

Three-point charges, two positive and one negative, each having a magnitude of 20

Generally, the -ve charge is mathematically given as

$Q+=\sqrt{x^2+x^2+2x.xcos120}\\\\Q+=\sqrt{2x^2+2x*(1/2)}$

Q+=X

Therefore

$x=\frac{Kq1q2}{r2}\\\\x=\frac{9*10^9*20*10^{-6}*20*10^{-6}}{(30*10^-2)^2}$

X=40N

For more information on Force

brainly.com/question/26115859

5 0

2 years ago

What is the mass of a child in a wagon that has a velocity of 10 m/s and a Momentum of 30 KG* M/S

LenKa [72]

Explanation:

sinces : Momentum = velocity × mass

then : 30 = 10 × m and m = 30 ÷ 10 = 3 kg

3 0

2 years ago