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serious [3.7K]
3 years ago
13

PLEASEEEE HELP ME OUT!

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0
There are no real solutions to that equation.
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Help!!!!!!!!!!!!!!<br><br> 2x+3=x-7
svlad2 [7]

Answer:

<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>10</u></em></h2>

Step-by-step explanation:

2x+3=x-7

=> 2x - x = - 7 - 3

=> <em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-10</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

4 0
3 years ago
Factor out the expression 2/3 (4x + 9) detailed explanation of how this is done please
krek1111 [17]

Answer:

\frac{8x}{3} + 6

Step-by-step explanation:

I think what you mean is to solve the expression. Lets do it!

\frac{2}{3} (4x + 9)

=> \frac{8x}{3} + 6

Therefore, \frac{8x}{3} + 6 is our answer

8 0
3 years ago
Read 2 more answers
A fair coin is tossed three times and the events A, B, and C are defined as follows: A: \{ At least one head is observed \} B: \
Yanka [14]

Answer:

a) P(A)=0.875

b) \text{P(A or B)}=0.875

c) \text{P((not A)  or B  or (not C))}=0.625

Step-by-step explanation:

Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.

To find : The following probabilities by summing the probabilities of the appropriate sample points ?

Solution :

The sample space is

S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}

n(S)=8

A: At least one head is observed

i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

n(A)=7

B: At least two heads are observed

i.e. B={HHH,HTT,TTH,THT}

n(B)=4

C: The number of heads observed is odd.

i.e. C={HHH,HTT,THT,TTH}

n(c)=4

a) Probability of A, P(A)

P(A)=\frac{n(A)}{n(S)}

P(A)=\frac{7}{8}

P(A)=0.875

b) P(A or B)

Using formula,

\text{P(A or B)}=P(A)+P(B)-\text{P(A and B)}

\text{P(A or B)}=\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{\text{n(A and B)}}{n(S)}

\text{P(A or B)}=\frac{7}{8}+\frac{4}{8}-\frac{4}{8}

\text{P(A or B)}=\frac{7}{8}

\text{P(A or B)}=0.875

(c) P((not A)  or B  or (not C))

A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

not A = {TTT} = 1

B={HHH,HTT,TTH,THT}

C={HHH,HTT,THT,TTH}

not C = {HHT,HTH,THH,TTT} = 4

So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5

\text{P((not A)  or B  or (not C))}=\frac{5}{8}

\text{P((not A)  or B  or (not C))}=0.625

4 0
3 years ago
Graph this equation on the coordinate plane. y=−2x+4
patriot [66]
Hope this help ……………………..

7 0
3 years ago
Find the GCF of the following monomials.<br><br> -50m4n7 and 40m2n10
Dima020 [189]

Answer:

Assuming you are asking for the Greatest Common Factor (GCF) of -50m^4n^7 and 40m^2n^{10} the answer is:

10m^2n^7

Step-by-step explanation:

To find the GCF we should first find the GCF of the coefficients 50 and 40 which is 10.

After factoring that out we need to take a look at the variable m. In monomial 1 we see that the highest exponent of m is 4 and in the second is 2. When finding GCF we take the smallest of the two exponents which is 2. Therefore the next part of our GCF monomial is m²

If we apply the same rule for n the smallest exponent is 7 resulting in the appending of n^{7} to the answer

After combining each of these GCF of 40 and -50 (10), m^4 and m² (m²), and n^7 and n^10 (n^7) the answer is:

10m^2n^7

7 0
3 years ago
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