PLEASEE HELPPLook at the diagram of two students pulling a bag of volleyball equipment. The friction force between the bag and t
he floor is 4 N. What is the net force acting on the bag? What direction is the bag moving in?
1 answer:
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Answer:
(a) p = 3.4 kg-m/s (b) 37.78 N.
Explanation:
Mass of a basketball, m = 0.4 kg
Initial velocity of the ball, u = -5.7 m/s (as it comes down so it is negative)
It rebounds upward at a speed of 2.8 m/s (as it rebounds so positive)
(a) Change in momentum = final momentum - initial momentum
p = m(v-u)
p = 0.4 (2.8-(-5.7))
p = 3.4 kg-m/s
(b) Impulse = change in momentum
Ft = 3.4
We have, t = 0.09 s
Hence, this is the required solution.
Answer: The temperature after another 5 minutes is 68.5°c
Explanation: Please see the attachments below
