PLEASEE HELPPLook at the diagram of two students pulling a bag of volleyball equipment. The friction force between the bag and t
he floor is 4 N. What is the net force acting on the bag? What direction is the bag moving in?
1 answer:
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The cyclist is moving by uniformly accelerated motion, with an initial velocity of 
and an acceleration of 
.
The acceleration is given by
where
is the final velocity and 
is the time between the end and the beginning of the motion, and in our case it is 1.75 s. Therefore, from this relationship we can find the final velocity:
The acceleration is given by
where
Answer:
<em>a. 10 years</em>
<em>b. 6 years</em>
<em>c. 12 years behind</em>
<em></em>
Explanation:
speed of light c = 3x m/s
distance of sirius from earth = 8 lightyears = 8 x c x 60 x 60 x 24 x 365 = 252288000c meters
speed of spaceship = 0.8c
time taken to reach sirius = distance covered divided by speed
t = d/s = 252288000c/0.8c = 315360000 sec
<em>1 year = 60 x 60 x 24 x 365 sec = 31536000 sec</em>
315360000 sec = 315360000/31536000 = <em>10 yrs</em>
<em>the time as observed by Goslo will be shorter than the real time as measured within the ship due to relativistic effects. using the relativistic relation for time dilation we have</em>
t' = t
since v = 0.8c
v/c = 0.8
where t' is the relativistic time as observed by Goslo,
t is the time within the ship
t' = 10 x = <em>6 yrs</em>
<em></em>
If speedo turns around immediately after reaching sirius, his total distance will be 252288000c x 2 = 50457600c meter
time taken = 50457600c/0.8 = 630720000 sec = 20 yrs
time within the ship will be calculated from time dilation
t' = t
t' = 20 x = 378432000 sec = <em>12 years behind</em>