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vivado [14]
3 years ago
7

How does the work needed to lift an object and the gravitational potential energy of an object compare

Physics
1 answer:
Ganezh [65]3 years ago
8 0

When you do work to lift the object, the amount of work you do BECOMES the object's gravitational potential energy.  It GETS its potential energy from the work you do to lift it.  They're equal.  You lose it, and the object gains it.  Energy is not created or destroyed.  It's just transferred from you to the object.  

Later, when you DROP the object, GRAVITY does the same amount of work on it, to pull it to the ground.  Again, no energy is created or destroyed.  Every time a force acts to move anything, the energy to do it comes from somewhere, and the energy goes somewhere.

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What is the total energy that the ball has when the launcher is in the ""ready to launch"" position with the spring fully compre
m_a_m_a [10]
Work is done when a spring is extended or compressed . Elastic potential energy is stored in the spring hope that helpss.
4 0
2 years ago
A Carnot engine has an efficiency of 0.537, and the temperature of its cold reservoir is 379 K.
katen-ka-za [31]

Answer:

(A) Th = 818.6 K

(B) Qh = 14211.7 J

Explanation:

efficiency (n) = 0.537

temperature of cold reservoir (Tc) = 379 K

heat rejected (Qc) = 6580 J

(A) find the temperature of the hot reservoir (Th)

 n = 1 - \frac{Tc}{Th}

0.537 = 1 - \frac{379}{Th}

\frac{379}{Th} = 1 - 0.537 = 0.463        

Th = \frac{379}{0.463}

Th = 818.6 K

(B) what amount of heat is put into the engine (Qh) ?

from \frac{Tc}{Th} = \frac{Qc}{Qh}

Qh = 6580 ÷ \frac{379}{818.6}

Qh = 14211.7 J

8 0
3 years ago
A 200 g block is pressed against a spring of force constant 1.40 kN/m until the block compresses the spring 10.0 cm. The spring
tino4ka555 [31]

Answer:

Explanation:

This problem bothers on the energy stored in a spring in relation to conservation of energy

Given data

Mass of block m =200g

To kg= 200/1000= 0.2kg

Spring constant k = 1.4kN/m

=1400N/m

Compression x= 10cm

In meter x=10/100 = 0.1m

Using energy considerations or energy conservation principles

The potential energy stored in the spring equals the kinetic energy with which the block move away from the spring

Potential Energy stored in spring

P.E=1/2kx^2

Kinetic energy of the block

K.E =1/mv^2

Where v = velocity of the block

K.E=P.E (energy consideration)

1/2kx^2=1/mv^2

Kx^2= mv^2

Solving for v we have

v^2= (kx^2)/m

v^2= (1400*0.1^2)/0.2

v^2= (14)/0.2

v^2= 70

v= √70

v= 8.36m/s

a. Distance moved if the ramp exerts no force on the block

Is

S= v^2/2gsinθ

Assuming g= 9. 81m/s^2

S= (8.36)^2/2*9.81*sin60

S= 69.88/19.62*0.866

S= 69.88/16.99

S= 4.11m

6 0
3 years ago
What would happen if the parent cell were to divide more times than usual during mitosis
SCORPION-xisa [38]

Answer:

Mitosis is a type of cell division in which a parent cell divides into two identical daughter cells, each with the same number and kind of chromosomes as the parent cell.

When a parent cell divides more times than usual during mitosis, the division of chromosomes between the chromosomes would not be proper. For example, a daughter cell may end up with one chromosome less than the parent cell. This ultimately results in genetic disorders.

4 0
3 years ago
Calculer l intensité du courant qui le traverse
MissTica

Answer:

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please mark me as brainalist

6 0
3 years ago
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