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Nezavi [6.7K]
3 years ago
7

Which statement is true about the inner planets of our solar system

Physics
1 answer:
poizon [28]3 years ago
4 0
B they formed from the dense elements as compared to the others in the solar system
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If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If, instead, you throw it downwar
Korvikt [17]

If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If instead, you throw it downward, its downward acceleration after release is 9.8 m/s2.

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration. Uniform acceleration, non-uniform acceleration, and average acceleration are the three different forms of accelerated motions.

A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth). This specific designation is given to the numerical value for an object in free fall because it is such an essential value. The longer an object is in free fall, the faster it descends toward the ground due to gravity. In actuality, an object's velocity rises by 9.8 m/s2, so it reaches 9.8 m/s by the time it begins to fall.

To know more about acceleration refer to: brainly.com/question/14468548

#SPJ4

4 0
2 years ago
A hockey puck slides across the ice and eventually comes to a stop. Why did the puck stop?
nignag [31]

Answer:

because it decrsces the force of momentome by sliding on the ice.

Explanation:

6 0
3 years ago
Read 2 more answers
A catapult with a radial arm 3.81 m long accelerates a ball of mass 18.2 kg through a quarter circle. The ball leaves the appara
saw5 [17]

Answer:

(a)\alpha = 53.73 m/s^2

(b)   I =428 kgm^2

(c)\tau = 428 \times 53.73  = 22996 .44Nm

Explanation:

GIVEN

mass = 18.2 kg

radial arm length = 3.81 m

velocity = 49.8 m/s

mass of arm = 22.6 kg

we know using relation between linear velocity and angular velocity

\omega = \frac{v}{l}

\omega = \frac{49.8}{3.81} \\\omega = 12.99 rad/s

for  angular acceleration, use the following equation.

\omega _{f}^2 = \omega_{i}^2+2\alpha\theta

since \omega _{i} = 0

here  for one circle is 2 π radians.   therefore for one quarter of a circle is π/2 radians

so   for one quarter \theta = \frac{\pi }{2}

(12.99)^2 = 2\alpha(\frac{\pi }{2})

on solving

\alpha = \frac{168.74}{\pi }\\\alpha = 53.73 m/s^2

(b)

For the catapult,

moment of inertia

I = \frac{1}{2}MR^2

I = \frac{1}{2} \times 22.6\times 3.81 \times 3.81\I = 164kg m^2

For the ball,

I = MR^2

I = 18.2 \times 14.51

I = 264 kgm^2

so total moment of inertia =  428 kgm^2

(c)

\tau = I\alpha

\tau = 428 \times 53.73  = 22996 .44Nm

3 0
4 years ago
What is the acceleration of a 10 kg object subject to a 25 N force?
timama [110]

Answer:

F=ma

F=25N

m=10kg

a=?

a=F/m

a=25/10

a=2.5m/s²

8 0
3 years ago
In A. C. motor capacitor is used
natita [175]

Answer:

d. to decrease D. C.

Explanation:

d. to decrease D. C.

4 0
3 years ago
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