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inn [45]
3 years ago
5

Give three examples of unbalanced forces in your everyday life. HELP FAST PLZ

Physics
2 answers:
evablogger [386]3 years ago
3 0
1. Kicking a soccer ball
2.Playing tug of war
3.Bouncing a Ball
antiseptic1488 [7]3 years ago
3 0

Answer:

1.    Kicking a soccer ball

2.      Playing tug of war  

3.         Bouncing a Ball

Explanation:

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What impulse occurs when an average force of 7.0 N is exerted on a cart for 2.5 s ?
makkiz [27]

Answer:1.7\times 10

Explanation:

Given

Force F=7 N

time interval t=2.5 s

Impulse is given by =Force \times time\ interval\ for\ applied\ force

Impulse=7\times 2.5=17.5

For two significant Figure

Impulse=1.7\times 10

                       

7 0
3 years ago
Draw the model of an atom with an atomic number of 7 and a mass number of 15. How many valence electrons are in this atom.
o-na [289]

Answer:

There are 5 valence electrons

Explanation:

Valence electrons are electrons found in the outermost shell of an atom.

7 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Match each expression to its simplified form.
Naddik [55]

Answer:

3a^5 - (-a^5) = 3a^5 + a^5 = 4a^5

6a^7 - 2a^7 = 4a^7

-3a^5 - (-2a^5) = -3a^5 + 2a^5 = -a^5

7a^7 - 8a^7 = -a^7

7 0
3 years ago
Read 2 more answers
The behaviors that light exhibits are reflection, refraction, diffraction, polarization, and dispersion. Answer
Molodets [167]
I believe the correct answer is false. The behaviors that light exhibits are reflection, refraction, diffraction but not polarization, and dispersion. Light<span> behaves as a wave - it undergoes reflection, refraction, and diffraction just like any wave would. Hope this answers the question.</span>
5 0
4 years ago
(5) A 4 kg. object rests on a flat, horizontal surface with a static
baherus [9]

Answer:

F = 9.81 [N]

Explanation:

To solve this problem we must use Newton's third le which tells us that the sum of forces on a body that remains static must be equal to one resulting from these forces in the opposite direction.

Let's perform a summation of forces on the vertical axis-y to determine the normal force N.

∑F = 0 (axis-y)

N - m*g = 0

where:

m = mass = 4 [kg]

g = gravity acceleration = 9.81 [m/s²]

N - (4*9.81)=0\\N = 39.24 [N]

Now we know that the frictional force can be calculated using the following equation.

f = μ*N

where:

f = friction force [N]

μ = friction coefficient = 0.25

N = normal force = 39.24 [N]

Now replacing:

f = 0.25*39.24\\f = 9.81[N]

Then we perform a sum of forces on the X-axis equal to zero. This sum of forces allows us to determine the minimum force to be able to move the object in a horizontal direction.

∑F = 0 (axis-x)

F-f=0\\F-9.81=0\\F= 9.81[N]

If the coefficient was smaller, a smaller force (F) would be needed to start the movement, this can be easily seen by replacing the value of 0.25, by smaller values, such as 0.1 or 0.05.

If the coefficient were larger, a larger force would be needed.

3 0
3 years ago
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