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lisov135 [29]
3 years ago
8

I NEED HELP PLEASE ASAP!! :) How many molecules are represented by 3CO2?

Chemistry
2 answers:
andriy [413]3 years ago
7 0
9. 3 Carbon and 6 Oxygen
barxatty [35]3 years ago
7 0

we can start by noting that there are three carbon atoms in each C3H8 molecule. thus, three CO2 molecules are formed for every C3H8 molecule consumed.

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A gas at 325 k has a volume of 4.0 L. If the gas’s volume changes to 2.0 L at constant pressure, what will be the new temperatur
inessss [21]
4/325 = 2/unknown temperature
unknown temperature= 2/(4/325)=162.5k
8 0
3 years ago
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How do you solve this
3241004551 [841]
With your mind. Boom. Lol I'm sorry I don't know I just need points
4 0
3 years ago
Physical science!!! please help
IgorLugansk [536]

Answer:

The correct answer is : No, because there are 4 hydrogen atoms on the reactants side and 2 on the products side.

Explanation:

NH_4NO_3\rightarrow N_2O+H_2O

The given reaction equation is not balanced because:

  • Number of hydrogen atoms  on both sides are not equal that is 4 on reactants side and 2 on products side.
  • Number of oxygen atoms on both sides are not equal that is 3 on reactants side and 2 on products side.

In a balanced chemical equation number of atoms of each elements are equal on both sides.

So, the balanced chemical equation will be:

NH_4NO_3\rightarrow N_2O+2H_2O

7 0
3 years ago
Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3 + C6H6 → H(C6H5+)SO3− [slow]
ziro4ka [17]

Question is incomplete, complete question is as follows :

Complete Question : .Sulfonation of benzene has the following mechanism:

(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3

[fast]

(2) SO3 + C6H6 → H(C6H5+)SO3−

[slow]

(3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4

[fast]

(4) C6H5SO3− + H3O+ → C6H5SO3H + H2O

[fast]

write the overall rate law for the initial rate of the reaction as a fraction.

Rate=k(________/_________)

Answer:

The overall rate law for the initial reaction is = k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

Explanation :

Frist of all, all the common terms are cancelled out and written the overall reaction.

As we know that the rate depednant step is the slowest step of the reaction, rate law is :

                        rate = k_{2} [SO_{3}][C_{6}H_{6}]

But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.

Rate law for synthesis of S03 is as follows :

                       rate = k_{1}[H_{2}SO_{4}]^{2}

Hence when we substitute equation 2 in equation one,

                   Rate comes out to be =  k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

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3 years ago
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Ierofanga [76]
Sunlight is collected from a renewable resource, which is naturally replenished one a human timescale
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