Question

A barium hydroxide solution is prepared by dissolving 2.81 g of Ba(OH)2 in water to make 25.6 mL of solution. What is the concentration of the solution in units of molarity

Answer 1

The concentration of the solution in units of molarity is 0.64 M and the concentration of the solution in terms of g/mL is 0.10976 g/mL.

What is the concentration of the solution?

The measure of the amount of the solute dissolved in the given amount of the solvent or solution is said to be the concentration of the solution.

It is given by the expression,

Concentration of the solution = mass of the solute/total volume of the solution

Units: g/mL

What is the concentration of the solution in units of molarity?

The concentration of the solution in units of molarity is given by the expression,

Molarity = (no. of moles of the solute)/(Volume in L)

Units: moles/L

Calculation:

It is given that the solute is barium hydroxide - Ba(OH)₂

The mass of Ba(OH)₂ = 2.81 g

When in dissolved in water, the total volume of the solution = 25.6 mL

The molar mass of Ba(OH)₂ = 171.34 g/mol

Then,

No. of moles = (mass of Ba(OH)₂)/(molar mass of Ba(OH)₂)

i.e.,

No. of moles = $\frac{2.81}{171.34}$ = 0.0164 mole

Concentration = mass of the solute/total volume

I.e., C = $\frac{2.81}{25.6}$ = 0.10976 g/mL

Then the concentration of the solution in units of molarity is,

Molarity = (no. of moles)/(Volume of the solution in L)

⇒ Molarity = $\frac{0.0164}{25.6/1000}$ = 0.64 M

Therefore, the concentration of the solution in units of molarity is 0.64 M.

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