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lakkis [162]
2 years ago
6

Jaclyn bought a PS4 game that was on sale for 20% less than the original price. The original price was $10 more than the sale pr

ice.
What was the ORIGINAL price?
Explain your answer.
Mathematics
1 answer:
vaieri [72.5K]2 years ago
7 0

Answer:

$50

Step-by-step explanation:

If the original price was $10 more than the sale price, so we know that in this case, 20% = $10. Because 20% is equivlalent to \frac{1}{5}, multiply $10 by 5 to get the answer of $50.

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A linear function and an exponential function are graphed below. Find possible formulas for the functions f(t), in blue, and g(t
Zielflug [23.3K]

Answer:

f(t) = -t + 21

g(t) = 18*e^( - t / 12 + 1/4 )

Step-by-step explanation:

Given:

- The graphs for the similar question is attached.

- The same graph would be used as reference but with different coordinates for point of intersection of f(t) and g(t) @ ( 3 , 18 ) & ( 15 , 6 ).

Find:

- The formulas for functions f(t) and g(t).

Solution:

- First we will determine f(t) the blue graph which is a "linear" function. The general equation for the linear function is given as:

                                    f(t) = m*t + c

Where, m: is the gradient  ( constant )

            c: The f(t) intercept. ( constant )

- The gradient m can be determined by the given points that lie on the graph:

                         m = ( f(t2) - f(t1) ) / ( t2 - t1 )

                         m = ( 6 - 18 ) / ( 15 - 3 )

                         m = -12 / 12 = -1

- The constant c can be evaluated by using any one point and m substituted back into the linear expression as follows:

                          f(t) = -t + c

                          18 = -(3) + c

                           c = 21

- The function f(t) is as follows:

                            f(t) = -t + 21

- The general expression for an exponential function can be written as:

                           g(t) = a*e^(b*t)

Where, a and b are constants to be evaluated.

- We will develop two expressions for g(t) using two given points that lie on the curve as follows:

                           18 = a*e^(3*b)

                           6 = a*e^(15*b)

- Divide the two expressions we have:

                           3 = e^( 3b - 15b )

                           Ln(3) = -12*b

                           b = - Ln(3) / 12

- Then the expression 1 becomes:

                          18 = a*e^( - Ln(3)*3 / 12)

                          18 = 3*a*e^(-1/4)

                           6 = a / e^(0.25)

                           a = 6*e^( 1 / 4 )

- The function g(t) can be expressed as:

                          g(t) = 18*e^( - t / 12 + 1/4 )

3 0
3 years ago
A triangle has a base of 7 1/8 feet and height 7 1/5 ft. what is the area as a mixed number
sleet_krkn [62]

The answer is 25 13/20 square feet.

In order to complete this operation, it is first best to change your mixed numbers into improper fractions.

7 1/8 = 57/8

7 1/5 = 36/5

Now that we have these, we can put them into the triangle formula.

A = 1/2bh

A = (1/2)(57/8)(36/5)

A = 1026/40

You can then simplify this fraction by dividing the top and bottom by a factor of 2.

A = 513/20

Then, because we know 20 goes into 500, 25 times, we can pull that out and be left with a remainder of 13/20.

A = 25 13/20

8 0
3 years ago
What is the principal, if the interest earned is $22, the simple annual interest rate is 2%, and the time is one year?
seropon [69]

Answer:

$1,100

Step-by-step explanation:

first find the principal first Multiply the rate 0.02 by the time 1 year this gives us 0.02 then divide the interest ($22) by 0.02 then you get $1,100.

Hope that helped!

4 0
2 years ago
Olivia will deposit $1,000 in an account that earns 6% interest compounded annually for 3 years. What is her total in the accoun
nata0808 [166]

Answer:

A= 1000(1+.06)^3 answer is A=1191.016

Step-by-step explanation:

first the formula is A=a(1 + or- R)^t

A=total

a=money or amount

R=rate it increase or decrease (percent) change to decimal

T=times,years,months ect..

6 0
3 years ago
6x4/12+72/8-9 using pemdas
V125BC [204]
Here ya go ^v^ try to use math.way
I hope this helps
Ya have a wonderful day ^v^

3 0
3 years ago
Read 2 more answers
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