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3 years ago

PLEASE HELP ASAP!!!!

Physics

2 answers:

sveticcg [70]3 years ago

8 0

Answer:

it's frequency

Explanation:

hope this helps :)

alexandr1967 [171]3 years ago

5 0

Answer:

its probably its frequency

Explanation:

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If molecules in a substance move FASTER will the TEMPERATURE increase or decrease?

statuscvo [17]

The temperature will increase

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4 years ago

A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a

stira [4]

Answer:

Explanation:

Given

acceleration is given by

$a=-g-c_Dv^2$

where $\ddot{y}=a$

$\dot{y}=v$

Also acceleration is given by

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ds=\frac{v}{a}dv$

$\int ds=\int \frac{v}{-g-0.001v^2}dv$

$\Rightarrow Let -g-0.001v^2=t$

$-0.001\times 2vdv=dt$

$vdv=-\frac{dt}{0.002}$

$at\ v_0=50\ m/s,\ t=-g-0.001(50)^2$

$t=-g-2.5$

at $v=0,\ t=-g$

$\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}$

$\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}$

$s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}$

$s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})$

$s=113.608\ m$

when air drag is neglected maximum height reached is

$h=\frac{v_0^2}{2g}$

$h=\frac{50^2}{2\times 9.8}$

$h=127.55\ m$

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3 years ago

Write forty million in scientific notation.

Ivanshal [37]

Answer: 4 x 106

That’s how you write forty million in scientific notation.

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3 years ago

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How many electrons are depicted in the electron dot diagram of an electrically neutral nitrogen atom? A. two B. six C. eight D.

goldenfox [79]

Answer is D - five.

<em>Explanation;</em>

- Electron dot diagrams show the valence electrons around the element by using dots.

- Valence electrons are the electrons which are in outermost shell of the atom.

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Atomic number = number of protons = 7

If the atom is neutral,

number of protons = number of electrons.

Hence, N atom has 7 electrons.

- The electron configuration is 1s² 2s² 2p³.

Hence, N atom has 2 + 3 = 5 valence electrons. So, five electrons are represented in electron dot diagram of N.

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il63 [147K]

I would say option D, it depends on the size of the star

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