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sergeinik [125]
3 years ago
5

Calculate the kinetic energy of a 1500 kg car moving at 42 km/hr.

Physics
1 answer:
yan [13]3 years ago
7 0
100920 Joole or whatever it’s called
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What is the rabbit's displacement from t = 0s to 3 s?<br> Answer with two significant digits.
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Answer: i think the answer is 20.0s

Explanation:

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You approach a railroad crossing with a cross buck sign that has no lights or gates. What should you do?
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Stop and look to see if anything is coming 
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How do you identify the number of valence electrons in an element using periodic table
frosja888 [35]
You may look at what group they are in
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1A=Group 1
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Three parallel wires each carry current I in the directions shown in (Figure 1). The separation between adjacent wires is d.
jasenka [17]

(a) The magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

(b) The magnitude of the net magnetic force per unit length on the middle wire is zero.

(c) The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

<h3>Force per unit length</h3>

The magnitude of the net magnetic force per unit length on the top wire is calculated as follows;

F₁/L = (μI₁/2π) x (I₂/d + I₃/d)

F₁/L = (μI/2π) x (I/d + I/d)

F₁/L = (μI/2π) x (2I/d)

F₁/L = μI²/πd

The magnitude of the net magnetic force per unit length on the middle wire is calculated as follows;

F₂/L = (μI₂/2π) x (I₃/d - I₁/d)

F₂/L = (μI/2π) x (I/d -  I/d) = 0

The magnitude of the net magnetic force per unit length on the middle bottom is calculated as follows;

F₃/L = (μI₂/2π) x (I₁/d + I₂/d)

F₃/L =  (μI/2π) x (I/2d + I/d)

F₃/L =  (μI/2π) x (3I/2d)

F₃/L =  3μI²/4πd

Thus, the magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

The magnitude of the net magnetic force per unit length on the middle wire is zero.

The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

Learn more about magnetic force here: brainly.com/question/13277365

#SPJ1

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Using a 40w light bulb for 12 hours will consume how much energy?
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Alot i bet good question
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