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sergeinik [125]
3 years ago
5

Calculate the kinetic energy of a 1500 kg car moving at 42 km/hr.

Physics
1 answer:
yan [13]3 years ago
7 0
100920 Joole or whatever it’s called
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A uniform plank of length 5.0 m and weight 225 N rests horizontally on two supports, with 1.1 m of the plank hanging over the ri
lawyer [7]

Answer:

x = 0.6034 m

Explanation:

Given

L = 5 m

Wplank = 225 N

Wman = 522 N

d = 1.1 m

x = ?

We have to take sum of torques about the right support point.  If the board is just about to tip, the normal force from the left support will be going to zero.  So the only torques come from the weight of the plank and the weight of the man.

∑τ = 0  ⇒     τ₁ + τ₂ = 0  

Torque come from the weight of the plank = τ₁

Torque come from the weight of the man = τ₂

⇒  τ₁ = + (5 - 1.1)*(225/5)*((5 - 1.1)/2) - (1.1)*(225/5)*((1.1)/2) = 315 N-m (counterclockwise)

⇒  τ₂ = Wman*x = 522 N*x   (clockwise)

then

τ₁ + τ₂ = (315 N-m) + (- 522 N*x) = 0

⇒  x = 0.6034 m

7 0
2 years ago
Question 4 of 10
Alexus [3.1K]

Answer:

22.3 kg•m/s

Explanation:

Apex;)

7 0
3 years ago
Brutus, a champion weight lifter, raises 220 kg a distance of 3.10 m. (a) how much work is done by brutus lifting the weights? j
Nana76 [90]
A) work = force * distance 
mass is not a force, weight is, so we have to find the weight of the block. 
Weight = mg 
Weight = (220kg)(9.8) 
Weight = 2156N 
Work = 2156N * 3.10m 
work = 6683.6J 
b) Since he is holding the weights, it's not moving, therefore, he doesn't do any work 
c) The answer is still the same amount of work when he lifted them. 
d) The answer is no since when he let go the weight, he doesn't apply any force to the weight. 
e) P = work/time 
P = 6683.6J / 2.1s 
P = 3182.67 watts 
3 0
2 years ago
Coherent light with wavelength = 600 nm falls on two very narrow closely spaced slits and the interference pattern is observed o
Mrac [35]

Answer:

The distance between the two slits is 1.2mm.    

Explanation:

The physicist Thomas Young establishes, through its double slit experiment, a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

\Lambda x = L\frac{\lambda}{d}  (1)

Where \Lambda x is the distance between two adjacent maxima, L is the distance of the screen from the slits, \lambda is the wavelength and d is the separation between the slits.  

If light pass through two slits a diffraction pattern in a screen will be gotten, at which each bright region corresponds to a crest, a dark region to a trough, as consequence of constructive interference and destructive interference in different points of its propagation to the screen.  

Therefore, d can be isolated from equation 1.

d = L\frac{\lambda}{\Lambda x}  (2)

Notice that it is necessary to express L and \lambda in units of millimeters.

L = 4m \cdot \frac{1000mm}{1m} ⇒ 4000mm

\lambda = 600nm \cdot \frac{1mm}{1x10^{6}nm} ⇒ 0.0006mm

d = (4000mm)\frac{0.0006mm}{2mm}

d = 1.2mm

Hence, the distance between the two slits is 1.2mm.

6 0
2 years ago
in coal-fired power plants, coal is burned to produce ____________________, which is then used to turn a turbine.
crimeas [40]
The answer is STEAM.
6 0
3 years ago
Read 2 more answers
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