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3 years ago

How many atoms of hydrogen are there in 3.0kg of ethane

1 answer:

7 0

Ethane has the formula C2H6.
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of hydrogen = 1 gram
Therefore:
molar mass of ethane = 2(12) + 6(1) = 30 grams

This means that each 30 grams of ethane contains 6 grams of hydrogen. To know how many grams of hydrogen are in 3000 grams of ethane (3 kg), we will simply use cross multiplication as follows:
mass of hydrogen = (3000 x 6) / 30 = 600 grams

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How do carrier proteins transport substances across cell membranes?

stepan [7]

<em>Transport of substances across cell membrane:</em>
<em>Carrier proteins facilitate transport of material across a membrane by changing its shape to allow a substance to pass through its membrane. It transports substances from high concentration to lower concentration levels.</em>

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3 years ago

URGENT

Vadim26 [7]

Answer:

Explanation:

Discussion

When Pressure increases equilibrium shifts to the side with the smallest number of moles. But which side is that?

N2(g) + 3H2(g) ⇌ 2NH3(g)

The left side has 1 mol of nitrogen (N2) and 3 moles of Hydrogen = 4 mols

on the left side.

The right side has 2 mols of NH3 = 2 mols on the right.

Conclusion: You tell the number of mols by the Balance numbers to the left of each chemical in an equation.

Since the left side N2 + 3H2 = 4 mols, the equilibrium does NOT shift left.

2NH3 is only two mols.

The equilibrium shifts Right

Answer

7 0

2 years ago

What determines the type of element that an atom makes?

Radda [10]

The number of protons, neutrons and electrons an atom has determines what element it is. Hydrogen, for example, has one proton, no neutrons and one electron; the element sulfur has 16 protons, 16 neutrons and 16 electrons.

4 0

2 years ago

Read 2 more answers

How many grams of oxygen can be prepared by the decomposition of 12 grams of mercury oxide<br><br>

Tom [10]

Taking into account the reaction stoichiometry, 0.886 grams of O₂ can be prepared by the decomposition of 12 grams of mercury oxide.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction of the decomposition of mercury oxide is:

2 HgO → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HgO: 2 moles
Hg: 2 moles
O₂: 1 mole

The molar mass of the compounds is:

HgO: 216.59 g/mole
Hg: 200.59 g/mole
O₂: 32 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

HgO: 2 moles ×216.59 g/mole= 433.18 grams

Hg: 2 moles ×200.59 g/mole= 401.18 grams

O₂: 1 mole ×32 g/mole= 32 grams

<h3>Mass of oxygen formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 433.18 grams of HgO form 32 grams of O₂, 12 grams of HgO form how much mass of O₂?

$mass of O_{2} =\frac{12 grams of HgOx 32 grams of O_{2}}{433.18 grams of HgO}$

<u><em>mass of O₂= 0.886 grams</em></u>

Then, 0.886 grams of O₂ can be prepared by the decomposition of 12 grams of mercury oxide.

Learn more about the reaction stoichiometry:

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7 0

2 years ago

Can the law of conservation of mass be applied when cooking? In one to two sentences, explain why or why not.

Slav-nsk [51]

Answer:

Explanation:

Of course. You cannot put in an 'x' amount of baking ingredients, then produce a meal that has more "mass" than what you have put in. Food will not spawn out of nowhere.

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2 years ago