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Tasya [4]
2 years ago
14

Plz help me fast plz !!!!!!

Chemistry
2 answers:
Ede4ka [16]2 years ago
4 0

Answer:

I and II      I think

Explanation:

Ipatiy [6.2K]2 years ago
4 0

Answer:ans would include iii

Explanation:

third one has most neutrons 14-6 = 8

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For questions #8 – 9 use the following pictures:
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3 years ago
The ph of a solution prepared by mixing 45.0 ml of 0.183 m koh and 35.0 ml of 0.145 m hcl is ________.
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Answer:

12.6.

Explanation:

  • We should calculate the no. of millimoles of KOH and HCl:

no. of millimoles of KOH = (MV)KOH = (0.183 M)(45.0 mL) = 8.235 mmol.

no. of millimoles of HCl = (MV)HCl = (0.145 M)(35.0 mL) = 5.075 mmol.

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So,

[OH⁻] = [(no. of millimoles of KOH) - (no. of millimoles of HCl)] / (V total) = (8.235 mmol - 5.075 mmol) / (80.0 mL) = 0.395 M.

∵ pOH = -log[OH⁻]

∴ pOH = -log(0.395 M) = 1.4.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 1.4 = 12.6.

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3 0
3 years ago
Read 2 more answers
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