Answer:
1.33 Å
Explanation:
Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å
Also,
For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.
Thus,
.................1
Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.
Thus,
...................2
Given that:
To find,
Using 1 and 2 , we get:
<u>Size of the potassium ion = 1.33 Å</u>
Answer:
l = 0, 1, and 2; it is in a d orbital.
Explanation:
1. Angular momentum quantum number
One square means l = 0.
Three squares mean l = 1.
Five squares mean l = 2.
If an atom contains electrons with l = 2, it must also have electrons with l = 0 and 1.
Thus, the electrons in the atom can be assigned the angular momentum quantum numbers l = 0, 1, and 2.
Those in a set of five squares all have l = 2.
2. Location of electron
The last electron is the lone electron in the fifth square. Since l = 2, the electron is in a d orbital.
