Answer:
35.6 liters at STP
Explanation:
The molar mass of carbon dioxide is about 44.01 g/mol. The volume of a mole of ideal gas at STP is 22.4 L, so the volume of 70.0 g will be ...
(70.0g)/(44.01 g/mol)·(22.4 L/mol) ≈ 35.6 L
MgCal2=Cal2
it is c trench marks
group 1, 2 and 3 tend to get rid of electrons and start to form compounds with groups 7, 6, and 5.
