Answer: The number of first-year residents she must survey to be 95% confident= 263
Step-by-step explanation:
When population standard deviation (
) is known and margin of error(E) is given, then the minimum sample size (n) is given by :-
, z* = Two-tailed critical value for the given confidence interval.
For 95% confidence level , z* = 1.96
As, = 8.265, E = 1
So, ![n= (\dfrac{1.96\times8.265}{1})^2 =(16.1994)^2\\\\= 262.42056036\approx263\ \ \ [\text{Rounded to the next integer}]](https://tex.z-dn.net/?f=n%3D%20%28%5Cdfrac%7B1.96%5Ctimes8.265%7D%7B1%7D%29%5E2%20%3D%2816.1994%29%5E2%5C%5C%5C%5C%3D%20262.42056036%5Capprox263%5C%20%5C%20%5C%20%5B%5Ctext%7BRounded%20to%20the%20next%20integer%7D%5D)
Hence, the number of first-year residents she must survey to be 95% confident= 263
Answer:
2fg
Step-by-step explanation:
False it is roughly 3.74 so it is less than 5. Becuase
if thats what ur asking lol
Answer:
3+3x+7 or 3x+10
Step-by-step explanation:
Given that percent of computer infected which is found by quality control inspector = 1.3%
Total number of computers = 1500
Now we have to find the number of Defective computer. To find that we will just need to find the product of given defective percent by the total number of computers.
Total number of defective computers = 1.3% of 1500
Total number of defective computers = 0.013* 1500
Total number of defective computers = 19.5
Hence final answer is approx 20 computers.
