You have to read 50 pages each day to finish the book.
Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
Combine like terms and then simplify
Answer:
2375^-3
Step-by-step explanation:
Move the decimal place from 2.375 to the back of the number so it should look like this, 2375.
Than move the decimal place back to its original spot and count the amount of spaces you move. Remember, if you move forward, your exponent should be negative. For example, if the problem is 6.321, you would move the decimal place to the back like this, 6321. And then move it back to where it originally was, 6.321, the amount of spaces I moved was 3 spaces and I moved forward so It would be 6.321^-3
