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neonofarm [45]
3 years ago
11

Please help I am doing this in class right now

Mathematics
1 answer:
MAVERICK [17]3 years ago
3 0

Answer:

I believe the answer is (9, -13.5)

Step-by-step explanation:

you do 6×1.5 and -9×1.5 to enlarge/dialate the quadrilateral

again I believe this is right so sorry if I am wrong

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Help me please. I need it rn​
cricket20 [7]

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3 years ago
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PLEASE HELP I'M TIMED
DedPeter [7]

Really hope i'm right

1st row

the first one is length less than 10

one next to it is width greater than 5

next to that is length greater than 10

2nd row

the first one is length greater than 10

one next to that is width less than 5

next to that is width greater than 5

3rd row

first one is width less than 5

and last is length less than 10

4 0
3 years ago
The length of a rectangle is eight feet more than its width. The area of the rectangle is six hundred nine square feet. What are
vodomira [7]
You can write two equations using the given information:
.. L = W +8
.. L * W = 609
Using substitution, you get a quadratic.
.. (W +8) * W = 609
.. W^2 +8W -609 = 0
Not surprisingly, you're looking for factors of 609 that differ by 8.
.. 609 = 1*609 = 3*203 = 7*87 = 21*29
The last two are the factors of interest.
.. (W +29)(W -21) = 0

The width of the rectangle is 21 feet, the length is 29 feet.

_____
Sometimes it is easier to work with the average dimension. Here, let that be x. Then you have
.. (x +4)(x -4) = 609
.. x^2 -16 = 609
.. x^2 = 625 = 25^2 . . . . . . . one of your memorized math facts
So, the dimensions are
.. 25 +4 = 29 by 25 -4 = 21, that is, 29 ft by 21 ft.
5 0
3 years ago
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