The pressure will not affect the rate of solution.
1) Chemical reaction: CH₄ + H₂O → 3H₂ + CO ΔH = + 206 kJ/mol.
2) Chemical reaction: CO + H₂O → CO₂ + H₂, ΔH = + 2,8 kJ/mol.
3) Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O ΔH = -802 kJ/mol.
4) Chemical reaction: 2H₂ + O₂ → 2H₂O ΔH = 2·(-242 kJ7mol) = - 484 kJ/mol.
Endothermic reaction (ΔH>o) and exothermic reaction (ΔH<span><0).</span>
41.38 % Mg
55.17 % O
3.45 % H
Explanation:
What is the percent composition of magnesium hydroxide Mg(OH)₂?
To find the percent composition we follow the next algorithm.
First we calculate the molar mass of Mg(OH)₂:
molar mass of Mg(OH)₂ = molar mass of Mg × 1 + molar mass of O × 2 + molar mass of H × 2
molar mass of Mg(OH)₂ = 24 × 1 + 16 × 2 + 1 × 2 = 58 g/mole
Now we devise the next reasoning:
if in 58 g of Mg(OH)₂ there are 24 g of Mg, 32 g of O and 2 g of H
then in 100 g of Mg(OH)₂ there are X g of Mg, Y g of O and Z g of H
X = (100 × 24) / 58 = 41.38 % Mg
X = (100 × 32) / 58 = 55.17 % O
X = (100 × 2) / 58 = 3.45 % H
Learn more about:
percent composition
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Answer:
Hydrogen: 5
Carbon:3
Nitrogen:3
Oxygen: 9
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The given question is incomplete. the complete question is:
The electron arrangement ions 
and 
are 2, 8, and 2, 8, 8 respectively.
Write the electronic arrangement of the elements X and Y.
Write the formula of the compound that would be formed between X and Y.
Answer: 1. The electronic arrangement for X and Y are 2,8, 3 and 2,8,5 respectively.
The formula of the compound formed is 
Explanation:
Electronic configuration is the arangement of electrons in an atom in order of increasing energies.
Cations are formed when electrons are lost by atoms and anions are formed when electrons are gained by atoms.
For formation of a neutral ionic compound, the charges on cation and anion must be balanced.
Here element X is having an oxidation state of +3 called as cation and is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral
