Answer:
The substance has a specific heat of 1.176 J/g°C
Explanation:
<u>Step 1: </u>Data given
Temperature change = 34 °C
Mass of the substance = 20 kg = 20000 grams
The substance gained 800 kJ of heat during this temperature change
<u>Step 2:</u> Calculate the specific heat
q = m*c*ΔT
⇒ with q = heat gained = 800 kJ = 800000 J
⇒ with m = the mass of the substance = 20 kg = 20000 grams
⇒ with c = the specific heat of the substance = TO BE DETERMINED
⇒ with ΔT = the change of temperature = T2 -T1 = 48° - 14 ° = 34°
c = q/(m*ΔT)
c = 800000 / (20000 * 34)
c = 1.176 J/g°C
The substance has a specific heat of 1.176 J/g°C
We can exemplify with H2O (water)
H= nonmetalic
O= Nonmetalic
A bond with nonmetalic and nonmetalic is covalent bond.
Hope it helps!!
#MissionExam001
Answer:
1.23 moles
Explanation:
Ideal gas law
PV = n RT R = .082057 L-atm/mol-K
25 C = 298.15 K
12 (2.5) = n (.082057) (298.15) n = 1.23 moles
calculate moles of both reagents given and the moles of FeS that each of them would form if they were in excess
moles = mass / molar mass
moles Fe = 7.62 g / 55.85 g/mol
= 0.1364 moles
1 mole Fe produces 1 mole FeS
Therefore 7.62 g Fe can form 0.1364 moles FeS
moles S = 8.67 g / 32.07 g/mol
= 0.2703 moles S
1 mole S can from 1 moles FeS
So 8.67 g S can produce 0.2703 moles FeS
The limiting reagent is the one that produces the least product. So Fe is limiting.
The maximum amount of FeS possible is from complete reaction of all the limiting reagent.
We have already determined that the Fe can form up to 0.1364 moles of FeS, so this is max amount of FeS you can get.
Convert to mass
hope this helps :)
<span>Their charges would be +2. When Group 2 elements lose two electrons they form positively charged ions (+2) ions. Magnesium, Calcium, Beryllium Strontium and Barium, lose their electron form positively charged Mg2+, Ca2+, Ba2+, Be2+ Sr2+ ions. These elements lose their electrons to obtain a noble gas electronic configuration.</span>