Answer:
AgNO₃(aq) + NaCl(aq) ⇄ AgCl(s)↓ + NaNO₃(aq) Kps
2K₃PO₄(aq) + 3MgCl₂(aq) ⇄ 6KCl (aq) + Mg₃(PO₄)₂ (s)↓ Kps
Explanation:
In the first reaction (1) we have:
Silver nitrate and sodium chloride as the reactants. Then the products will be, silver chloride (s) and sodium nitrate.
We know that all the salts from the nitrate are soluble, so the chloride will react to the silver cation to make the precipitate, an insoluble salt.
AgNO₃(aq) + NaCl(aq) ⇄ AgCl(s)↓ + NaNO₃(aq) Kps
For the second reaction (2), the reactants are:
Potassium phosphate and magnessium chloride
Phosphate salts are insoluble, except for the group 1. The same as chloride that makes soluble salts with the elements from the group 1.
The equation that makes the precipitate is.
2K₃PO₄(aq) + 3MgCl₂(aq) ⇄ 6KCl (aq) + Mg₃(PO₄)₂ (s)↓ Kps
Answer:
2523.23 cal / g
Explanation:
Mass = 6.80g
Temperature increase (T2 - T1) = 2.25
Heat capaity of calorimeter = 32.00kJK-1 = 7.64818 KcalK-1 ( Converting to calories by multiplying by 4.18)
Heat capacity = 7648.18 cal (converting to cal by mutltiplying by 1000)
Heat capacity = Heat Supplied / Temperature rise
Heat Supplied = Heat capacity * Temperature rise
Heat supplied = 7648.18 * 2.25
Heat Supplied = 17208.405 cal
To obtain the per gram value, we divide by the mass.
This gives us; 17208.405 / 6.80 = 2523.23 cal / g
<span>C. It is in the row below and therefore more reactive </span>