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swat32
3 years ago
5

1. Directions: Select each correct answer.

Chemistry
2 answers:
Kazeer [188]3 years ago
6 0
A and D! Bio means life so biotic factors are the living organisms.
Rom4ik [11]3 years ago
4 0
I do believe its is A. all types of plants
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What part of a chemical is represented by the letters
bonufazy [111]

Answer:

It's compound? It's chemical compound would be represented my letters or numbers

3 0
2 years ago
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30g of naoh is dissolved in 1.5 liter solution the active mass of naoh is?
Pepsi [2]

Answer:

0.5mol/L

Explanation:

First, let us calculate the number of mole NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the question = 30g

Number of mole = Mass /Molar Mass

Number of mole = 30/40 = 0.75mol

Volume = 1.5L

Active mass = mole/Volume

Active mass = 0.75mol/1.5L

Active mass = 0.5mol/L

7 0
3 years ago
Name the feature of the ocean floor shown at A and describe how it’s formed.
shusha [124]

Answer:

Scientists found that seams formed mountain ranges that ran along the middle of some ocean floors. Scientists found that mid ocean ridges extend into all of earth's oceans and that a steep sided valley splits the tops of some mid ocean ridges.

Explanation:

5 0
3 years ago
A throat lozenge contains 5.0 mg of menthol, which has the formula c10h20o.
Pachacha [2.7K]
A) 
the molecular formula of menthol is C₁₀H₂₀O 
molar mass of menthol is (12x10) + (1x20) + 16 = 156 g/mol
number of moles of menthol in 156 g - 1 mol
In 1 g of menthol number of moles - 1/156 
Therefore in 5.0 g of menthol - 1/156 x 5 = 0.032 mol
therefore in 5.0 g of menthol there are 0.032 mol of menthol

b)
Molar mass of menthol - 156 g/mol
1 mol of menthol weighs 156 g
Therefore 1.56 mol of menthol weighs - 156 g/mol x 1.56 mol = 243.36 g
5 0
3 years ago
We put 50 g of ice of 0 °C in a beaker containing 450 g of beer of 20 °C, mix, and wait for heat exchange within the beaker. Wha
erastova [34]

Answer : The final temperature will be, 292 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of ice = 2.05J/g.K

c_2 = specific heat of beer = 4.2J/g.K

m_1 = mass of ice = 50 g

m_2 = mass of beer = 450 g

T_f = final temperature = ?

T_1 = initial temperature of ice = 0^oC=273+0=273K

T_2 = initial temperature of beer = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

50g\times 2.05J/g.K\times (T_f-273)K=-450g\times 4.2J/g.K\times (T_f-293)K

T_f=291.971K\approx 292K

Therefore, the final temperature will be, 292 K

5 0
2 years ago
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