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swat32
3 years ago
5

1. Directions: Select each correct answer.

Chemistry
2 answers:
Kazeer [188]3 years ago
6 0
A and D! Bio means life so biotic factors are the living organisms.
Rom4ik [11]3 years ago
4 0
I do believe its is A. all types of plants
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Imagine that you run this experiment and that the initial change in pressure is 0.0023 atm/s. what is the initial reaction rate?
svet-max [94.6K]

\text{reaction rate} = 9.6 \times 10^{-5} \; \text{mol}\cdot\text{L}^{-1} \cdot \text{s}^{-1}

Explanation:

Concentration c = n / V;

The reaction see a 0.0023 \; \text{atm} change in pressure per second. By the ideal gas law, this quantity would correspond to a change in concentration, n/V of

c = n / V = P / (n \cdot R) = 0.0023 / ((273.15 + 20) \times 0.0821 ) = 9.6 \times 10^{-5} \; \text{mol}

where the ideal gas constant R = 0.0821 \; \text{L} \cdot \text{atm} \cdot \text{mol}^{-1} \cdot \text{K}^{-1}.

By definition, \text{reaction rate} = \Delta \text{concentration} / \Delta\text{time}

Therefore, for this particular reaction

\text{rate} = 9.6 \times 10^{-5} \; \text{mol} / (1 \; \text{s} ) = 9.6 \times 10^{-5} \; \text{mol}  \cdot \text{L}^{-1} \cdot \text{s}^{-1}

6 0
3 years ago
A mixture of ch4 and h2o is passed over a nickel catalyst at 1000. k. the emerging gas is collected in a 5.00-l flask and is fou
Scrat [10]
                    
According to that Kc is an equilibrium constant in terms of molar concentrations.
and Kc = [C]^c *[D]^d / [A]^a * [B]^b >>>> (1)
in the general reaction:
aA + bB ↔ cC + dD 
and, from our balanced equation:
CH4 + H2O ⇔ Co + 3H2 >>> (2)
So, we need to calculate the concentrations (molarity) of the products and reactants:
the Molarity of CH4 = no. of moles/volume (L)
 and no. of moles = weigh / Molecular weight = 42.3 / 16 = 2.643 moles
so the molarity of CH4 = 2.643 / 5 = 0.528 molar
the molarity of H20 = (49.2 / 18) / 5 =  0.546 molar
the molarity of CO = (8.32/28) / 5 = 0.059 molar
the molarity of H2 = (2.63 / 2) / 5 = 0.263 molar 
By substitution in (1) according to (2);
∴ Kc = [0.059]*[0.263]^3 / ( [0.528]*[0.546]) = 3.7 * 10 ^-3  >>>> (3)
Kp = Kc (RT)^(Δn) >>> (4)
where R is the gas constant = 0.0821,
and Δn is the change in moles in gas= (3(H2) + 1 (CO) - (1 H2O + 1 CH4) = 2
by substition in (4):
∴ Kp = 3.7*10^-3 (0.0821* 1000)^2= 24.939



3 0
3 years ago
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