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ivanzaharov [21]
2 years ago
12

Please help me figure this out!!!!

Mathematics
1 answer:
Ganezh [65]2 years ago
6 0
Angie P is 131 degrees

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Awnser this pls im in a bad mood
Drupady [299]

Answer:

I think its 1/6 and if I'm wrong I'm very sorry but I think its 1/6

Step-by-step explanation:

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in 2012 costsaver supermarkets sold groceries for £536480. it was increased by 12%on th 2011 figure. Find the value of the groce
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£600857.6Is the answer I believe.
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In how many ways can the letters in the word 'Illinois' be arranged?
xenn [34]

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The numbers of ways to permute letters of the word Illinois if the two Ls must be consecutive is 7.

7 0
3 years ago
A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran
Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0
3 years ago
Find the sum of the geometric sequence. (1 point) 1, one divided by two, one divided by four, one divided by eight, one divided
Firlakuza [10]
GP = 1/2 , 1/4 , 1/8 , 1/16
1st) the common ratio is (1/4 : 1/2 ) = 1/2, so r =1/2
2nd) the sum of a GP is:

S= a(1-rⁿ)/(1-r)

S=(1/2).[1-(1/2)⁴]/(1-1/2) = 15/16

6 0
3 years ago
Read 2 more answers
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