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AlexFokin [52]
3 years ago
13

When a photon collides with an electron and is deflected, the photon’s ____ decreases.

Physics
2 answers:
masha68 [24]3 years ago
7 0

Answer:

2. Wavelength

Explanation:

When a photon collides with an electron and is deflected, the photon’s wavelength decreases.

When photon gained energy by the collision of the electron. Its energy and frequency will be increased and its wavelength will be decreased.

77julia77 [94]3 years ago
7 0

Answer:

1. Frequency

Explanation:

When a photon collides with an electron, the effect of it is called Compton scattering, where the photons interact with the electron, losing momentum and therefore increase in wavelength and a decrease in frequency.

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Two balloons are charged with an identical quantity and type of charge: -4 nc They are held apart at a separation distance of 70
blagie [28]

Answer:

29.4 uN

Explanation:

The electric force between two charges can be calculated using Coulomb's Law. According to this law the force between two point charges is given as:

F=k\frac{q_{1} q_{2} }{r^{2}}

where k is a proportionality constant known as the Coulomb's law constant. Its value is 9 \times 10^{9} Nm²/C²

r = distance between charges = 70 cm = 0.7 m

q1 = q2 = 4nC = 4 \times 10^{-9} C

The negative sign indicates that the charges are negative. In the formula we will only use the magnitude of the charges.

Using these values in the formula, we get:

F=9 \times 10^{9} \times \frac{4 \times 10^{-9} \times 4 \times 10^{-9}}{0.7^{2}}\\\\ F=2.94\times10^{-7} N\\\\ F=29.4 \times 10^{-6} N\\\\ F=29.4 \mu N

Therefore, the magnitude of repulsive force between the given charges will be 29.4 uN

8 0
3 years ago
How does the configuration of the electric field occur between a "parallel plate" setup in a lab?What is the effect of conductor
sleet_krkn [62]

Explanation:

The magnitude of the electric field between the plates is given by

E = -ΔV/d

minus sign indicates Potential decreases in the direction of electric field

where

ΔV is the potential difference between the plates

D is the distance between the plates.

The work done when carrying an electrical charge on an equipotential surface between one position to the other is zero W= q(V-V)=0 The electric field lines of force are always perpendicular to an equipotential surface.  That conductor in an equipotential surface as direction E is at right angles to an eauipotential surface The intensity of the electric field along an equipotential surface is always zero. Equipotential surfaces never collide with each other as this would mean that at that point, there are two alternative values that are not true.

8 0
2 years ago
g (12 points) The time between incoming phone calls at a call center is a random variable with exponential density p(x) = 1 r e
rusak2 [61]

Answer:

(1)p(x)\geq 0\\(2)\int_{0}^{\infty} p(x) dx=0

Explanation:

A function f(x) is a Probability Density Function if it satisfies the following conditions:

(1)f(x)\geq 0\\(2)\int_{0}^{\infty} f(x) dx=0

Given the function:

p(x)=\dfrac{1}{r}e^{-x/r} \: on\: [0,\infty), where\:r=\dfrac{20}{ln(2)}

(1)p(x) is greater than zero since the range of exponents of the Euler's number will lie in [0,\infty).

(2)

\int_{0}^{\infty} p(x)=\int_{0}^{\infty} \dfrac{1}{r}e^{-x/r}\\=\dfrac{1}{r} \int_{0}^{\infty} e^{-x/r}\\=-\dfrac{r}{r}\left[e^{-x/r}\right]_{0}^{\infty}\\=-\left[e^{-\infty/r}-e^{-0/r}\right]\\=-e^{-\infty}+e^{-0}\\SInce \: e^{-\infty} \rightarrow 0\\e^{-0}=1\\\int_{0}^{\infty} p(x)=1

The function p(x) satisfies the conditions for a probability density function.

6 0
3 years ago
The engine on a fighter airplane can exert a force
DerKrebs [107]
Yes it can because it had lots of force
8 0
3 years ago
Jamie hears a high-pitched sound that then changes to a low-pitched sound. What is most likely occurring?
netineya [11]
 Below are the choices that can be found from other source:

a. frequency
b. the Doppler effect
c. the resonance effect
<span>d. intensity

The answer is B. 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
</span>
3 0
2 years ago
Read 2 more answers
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