Answer:
Distance = displacement = 35m
Explanation:
The distance of the student is how far he has gone.
Distance = 25m + 10m
Distance = 35m
Displacement is the distance specified in specific direction. Since the student walk in the sane direction, thence the displacement is also 35m
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Explanation:
It is given that,
Magnetic field, B = 0.15 T
Charge on a proton, ![q=1.60218\times 10^{-19}\ C](https://tex.z-dn.net/?f=q%3D1.60218%5Ctimes%2010%5E%7B-19%7D%5C%20C)
Mass of a proton, ![m=1.67262 \times 10^{-27}\ kg](https://tex.z-dn.net/?f=m%3D1.67262%20%5Ctimes%2010%5E%7B-27%7D%5C%20kg)
The cyclotron frequency is given by :
![f=\dfrac{qB}{2\pi m}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7BqB%7D%7B2%5Cpi%20m%7D)
![f=\dfrac{1.60218\times 10^{-19}\ C\times 0.15\ T}{2\pi \times 1.67262 \times 10^{-27}\ kg}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B1.60218%5Ctimes%2010%5E%7B-19%7D%5C%20C%5Ctimes%200.15%5C%20T%7D%7B2%5Cpi%20%5Ctimes%201.67262%20%5Ctimes%2010%5E%7B-27%7D%5C%20kg%7D)
f = 2286785.40 Hz
or
![\omega=14368296.44\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D14368296.44%5C%20rad%2Fs)
![\omega=1.43\times 10^7 rad/s](https://tex.z-dn.net/?f=%5Comega%3D1.43%5Ctimes%2010%5E7%20rad%2Fs)
Hence, this is the required solution.