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Law Incorporation [45]
3 years ago
13

Why do animals float when they die​

Physics
1 answer:
Gnom [1K]3 years ago
6 0

Answer:

they don't float when they die unless they are in water

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Two automobiles of equal mass approach an intersection. One vehicle is traveling with velocity 14.0 m/s toward the east and the
Sergeeva-Olga [200]

Answer:

kqwwwwj

Explanation:

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This exists in the space surrounding a charged particle and exerts a force on other charged particles.
Zinaida [17]

Gravitational field exists in the space surrounding a charged particle and exerts a force on other charged particles. Gravitational waves are ripples of waves travelling outward from the source. The more massive the orbit of two bodies, the more it emits gravitational wave. And everything around it that is near within the wave experiences a ‘pull’ toward the orbiting bodies.

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_______ measures an object's change in position per unit time.
Deffense [45]

I believe your answer should be C. Speed.

6 0
3 years ago
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A tin atom has 50 electrons. Electrons in the ________ subshell experience the lowest effective nuclear charge.
Alexus [3.1K]

Answer:

5p

Explanation:

We are given that a tin has 50 electrons.

We have to find in which subshell electrons experience the lowest effective nuclear charge.

We know that the electron in outermost shell experience the lowest effective nuclear charge.

Electronic configuration is given by

50=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^2

Outer most sub-shell is 5p. Therefore, 5p subshell experience the lowest effective nuclear charge because the distance of 5p sub-shell is large from nucleus.

Answer: 5p

5 0
3 years ago
satellite is placed in an elongated elliptical (not circular) orbit around the Earth. At the point in its orbitwhere it is close
GrogVix [38]

Answer:

a) v2=4147.72 m/s

b) stotal=5.53x10^6 m

Explanation:

a) the length from the center of the earth is equal to:

L1=1x10^6+((6.37/2)x10^6)=4.18x10^6 m

the velocity is 5.14 km/s=5.14x10^3 m/s

the farthest distance is equal to:

L2=2x10^6+((6.37/2)x10^6)=5.18x10^6 m

As the angular momentum is conserved, we have to:

I1=I2

m*L1*v1=m*L2*V2, where m is the mass of satelite

clearing v2:

v2=(L1*V1)/L2=(4.18x10^6*5.14x10^3)/5.18x10^6=4147.72 m/s

b) Using the Newton 3rd law:

vf^2=vi^2+2as

where:

a=g=9.8 m/s^2

vf=0

vi=5.14 km/s

s=?

Clearing s:

s=(vf^2-vi^2)/(2g)=((0-(5.14x10^3)^2)/(2*9.8)=1.35x10^6 m

the total distance is equal to:

stotal=s+L1=1.35x10^6+4.18x10^6=5.53x10^6 m

8 0
3 years ago
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