Because of the symmetry, we can just go from x=0 to x=2 to find the area between
<span>y = x^2 and y = 4 </span>
<span>that area = ∫4-x^2 dx from 0 to 2 </span>
<span>= [4x - (1/3)x^3] from 0 to 2 </span>
<span>= 8 - 8/3 - 0 </span>
<span>= 16/3 </span>
<span>so when y = b </span>
<span>x= √b </span>
<span>and we have the area as </span>
<span>∫(b - x^2) dx from 0 to √b </span>
<span>= [b x - (1/3)x^3] from 0 to √b </span>
<span>= b√b - (1/3)b√b - 0 </span>
<span>(2/3)b√b = 8/3 </span>
<span>b√b =4 </span>
<span>square both sides </span>
<span>b^3 = 16 </span>
<span>b = 16^(1/3) = 2 cuberoot(2) </span>
<span>or appr 2.52</span>
Answer:
(x-5)(x+5)
Step-by-step explanation:
HP = JP (since the opposite sides of an isosceles triangle are equal)
3x - 6 = x + 2
2x = 8
x = 4
Thus, HP = 3(4) - 6 = 12 - 6 = 6
JP = 4 + 2 = 6
JH = 2(4) = 8.
Answer:
Given
in a circle
Diameter ( d) = 36 cm
Then we have the formula that
Radius (r) = d / 2
= 36 / 2 = 18 cm
Answer:
6?5
Step-by-step explanation:
