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Y_Kistochka [10]
2 years ago
7

Can you please solve this​

Mathematics
1 answer:
ddd [48]2 years ago
7 0
The answer to your question is a=124 because the center triangle is a isosceles triangle
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20 POINTS! Please help, best answer will recessive brainliest answer points as well as 5 stars and a thank you. :)
valentina_108 [34]

Answer:

(3) Diagonals are perpendicular

Step-by-step explanation:

5 0
2 years ago
In 1985, there were 285 cell phone subscribers in Arlington. The number of subscribers increased by 75% per year since 1985. Fin
ANTONII [103]

Answer:

The number of subscribers in 2008 is 110,845,988

Step-by-step explanation:

The number of cell phone subscribers in Arlington, in t years after 1985, can be modeled by the following equation.

N(t) = N(0)(1+r)^{t}

And which N(0) is the number of subscribers in 1985 and r is the rate it increases per year, as a decimal.

In 1985, there were 285 cell phone subscribers in Arlington.

This means that N(0) = 285

The number of subscribers increased by 75% per year since 1985.

This means that r = 0.75

So

N(t) = 285(1.75)^{t}

Find the number of subscribers in 2008.

2008 is 2008-1985 = 23 years after 1985. So we have to find N(23).

N(23) = 285(1.75)^{23} = 110,845,988

The number of subscribers in 2008 is 110,845,988

8 0
2 years ago
What is the measure for angle CBD <br> PLSSS HELPP!!!!​
Andrei [34K]

The measure of the angle CBD = 180° - 30° = 150°.

3 0
2 years ago
A cylinder has a base area of 44.6 mm2 and a height of 24 mm.
Free_Kalibri [48]
Volume of cylinder = base area  x height
                            = 44.6 x 24
                            = 1070.4 mm³
7 0
3 years ago
Read 2 more answers
Find the multiplicative inverse of 6 + 2i
Marina CMI [18]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2774989

________________


Find the multiplicative inverse of

\mathsf{z=6+2i}

________


The inverse multiplicative of  \mathsf{z=a+bi}  is

\mathsf{\dfrac{1}{z}}\\\\\\&#10;=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\&#10;=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\&#10;=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}

=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\&#10;\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}

________


For this question,

\mathsf{z=6+2i}


So,

\mathsf{\dfrac{1}{z}}\\\\\\&#10;=\mathsf{\dfrac{1}{6+2i}}\\\\\\&#10;=\mathsf{\dfrac{6}{6^2+2^2}-\dfrac{2}{6^2+2^2}\,i}\\\\\\&#10;=\mathsf{\dfrac{6}{36+4}-\dfrac{2}{36+4}\,i}\\\\\\&#10;=\mathsf{\dfrac{6}{40}-\dfrac{2}{40}\,i}


\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)

6 0
3 years ago
Read 2 more answers
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