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yan [13]
4 years ago
11

A mover hoists a 200 kg piano from the ground to a height of 10 m using a single pulley. What was the change in the pianos energ

y? a. 20j b. 200j c. 2000j d. 20000
Physics
2 answers:
RideAnS [48]4 years ago
7 0
P.E= Mass x gravity x height   (standard gravity = 10m/s approaximately)
     = 200x10x10= 20000j (D)
aivan3 [116]4 years ago
3 0

Answer: d. 20000 J

Explanation:

Potential energy is the energy possessed by an object by virtue of its position.

P.E=m\times g\times h

m= mass of object = 200 kg

g = acceleration due to gravity = 10ms^{-2}

h = height of an object

1. when h= 10 m

P.E=200\times 10ms^{-2}\times 10m=20000Joules

2. when h= 0 m

P.E=200\times 10ms^{-2}\times 0m=0Joules

Thus change in energy=(20000-0)Joules=20000Joules.

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Explanation/Answer:

Wind turbines are more likely to be found near rural communities due to the large requirement for space.

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A rectangular piece of​ cardboard, whose area is 352 square​ centimeters, is made into an open box by cutting a 2​-centimeter sq
Usimov [2.4K]

Answer:

Dimension of cardboard is 22 m by 16 m

Explanation:

Given that,

Area = 352 cm²

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Volume of box = 432 cm³

Let the two sides are x and y.

The area of the rectangular piece is

xy=352

y=\dfrac{352}{x} -------- (1)

The volume of the rectangular piece

2(x-4)(\dfrac{352}{x}-4)=432

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x=16,22

Put the value of x in the equation (I)

For x = 16

y=\dfrac{352}{16}=22

For x = 22

y=\dfrac{352}{22}=16

Dimension of cardboard is 22 m by 16 m

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4 years ago
What type of local wind would you experience if you were standing in the valley? Explain your answer.
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Less wind because of the moutians
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A car with a mass of 2.0 * 10^3 kg is traveling at 15 m/s. what is the momentum of the car?
Allushta [10]
Hello,


Your answer to this problem is 400/3


Hope this helps!
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3 years ago
A bullet leaves a gun with a horizontal velocity of 100 m/s. Calculate the distance it would travel in 1.3 seconds.
stiks02 [169]

Ignoring air resistance, the bullet's horizontal velocity is constant:

v_x=v_{0x}=100\,\dfrac{\mathrm m}{\mathrm s}

In 1.3 seconds, we can expect it to travel

v_xt=\left(100\,\dfrac{\mathrm m}{\mathrm s}\right)(1.3\,\mathrm s)=130\,\mathrm m

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3 years ago
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