Answer:
An ionic bond is an attraction between ions of opposite charge in an ionic compound.
Answer:
When electron jumps from high energy level to lower energy level.
Explanation:
The elctronic transition from one energy level to another energy level within the atom, always involve energy transitions.
The energy released or absorbed by electronic transition is always discrete and is called as " Photon". It means when electron jumps from when energy level to another energy level the energy released or absorbed is treated as photon emitted or absorbed.
When an electron jumps from higher energy level to a lower energy level, a photon of specific wavelength and specific energy is emitted in other words we can say that energy is released or emitted.
The energy of photon emitted or absorbed is easily calculated using Rydberg Formula which is simply the energy difference between the two energy levels and is given as under;
Ephoton = Eo ( 1 / n1^2 - 1 / n2 ^ 2)
In the above formula n1 is the initial energy level of electron and n2 is the final energy level of electron.
Eo = 13.6 eV ( Here "o" in Eo is in subscripts)
In n1 and n2 1 and 2 are in the subscripts.
^ represents that the disgits after them are exponents.
So by just putting the values of energy levels n1 and n2 we can easily calculate the value of energy of photon ( energy due to electronic transition) and compare the results that which transition will give high energy photon and which will give low energy photon.
The 0.05 moles of
required to make 1 L of solution in which the
concentration is 0. 15 M.
Calculation,
The Sodium phosphate dissolves as follows:
→ 
To make 1. L of solution in which the
concentration is 0. 15 M
The morality of
= 0.15 M = number of moles / volume in lit
The morality of
= 0.15 M = number of moles /1 Lit
number of moles of
= 0.15 mole
The mole ratio is 1: 3
It means, the 1 mole of
required to form 3 mole of
So, to form 0.15 mole of
= 1×0.15 / 3 moles of
required.
Hence, number of moles of
required = 0.05 moles.
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Answer:

Explanation:
Density is found dividing mass by volume. In this case, we treat krypton as a sphere having a volume of
. Given:


We obtain density of:


This is not a feasible value for a gas like krypton, its radius is actually not 110 pm.