Answer: 0.52 L of 15 M 
will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base
Well do you have any answer choices and organic is mostly living so whatever answer that is a living thing like plants, animals, humans etc.
Answer is: Ksp for strontium arsenate is 2.69·10⁻¹⁸.
Balanced chemical reaction (dissociation):
Sr₃(AsO₄)₂(s) → 3Sr²⁺(aq) + AsO₄³⁻(aq).
s(Sr₃(AsO₄)₂) = 0.0650 g/L.
s(Sr₃(AsO₄)₂) = 0.0650 g/L ÷ 540.7 g/mol = 1.2·10⁻⁴ mol/L.
s(Sr²⁺) = 3s(Sr₃(AsO₄)₂).
s(AsO₄³⁻) = 2s(Sr₃(AsO₄)₂).
Ksp = s(Sr²⁺)³ · s(AsO₄³⁻)².
Ksp = (3s)³ · (2s)².
Ksp = 108s⁵.
Ksp = 108 · (1.2·10⁻⁴ mol/L)⁵ = 2.69·10⁻¹⁸.
The thick soil accumulation of fine-grained particles is called as silt
Answer:
That means, under 10.0kPa of pressure, 0.4g of gas can be dissolved in 1L
Explanation:
Based on Henry's law, the solubility of the gas is directly proportional to the pressure. The equation is:
P1S2 = P2S1
<em>Where P is pressure and S solubility of 1, initial state and 2, final state of the gas.</em>
Replacing:
P1 = 50.0kPa
S1 = 2.0g/L
P2 = 10.0kPa
S2 = ??
50.0kPa*S2 = 10.0kPa*2.0g/L
S2 = 0.4g/L
That means, under 10.0kPa of pressure, 0.4g of gas can be dissolved in 1L
