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evablogger [386]
3 years ago
14

Sodium and phosphorus combine to form Na3P. The name of this compound is .

Physics
2 answers:
Inessa [10]3 years ago
8 0

Answer: sodium phosphide

Explanation:

Na_3P is an ionic compound because sodium is a metal which forms Na^+ by loss of electron.

Phosphorous is a non-metal and The bond formed between a metal and a non-metal is always ionic in nature.

The nomenclature of ionic compounds is given by:

1. Positive is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

Hence, the name of Na_3P is sodium phosphide.

g100num [7]3 years ago
5 0
Binary ionic compound
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Identify the factors that cause melting and thus the formation of magma. Choose one or more: A. decompression B. compression C.
nordsb [41]

Answer: C Heat Transfer, E Addition of Volatiles and A Decompression

Explanation:

- Decompression melting takes place within Earth when a body of rock is held at approximately the same temperature but the pressure is reduced.

8 0
4 years ago
Consider two massless springs connected in parallel. Springs 1 and 2 have spring constants k1 and k2 and are connected via a thi
77julia77 [94]

Answer:

k1 + k2

Explanation:

Spring 1 has spring constant k1

Spring 2 has spring constant k2

After being applied by the same force, it is clearly mentioned that spring are extended by the same amount i.e. extension of spring 1 is equal to extension of spring 2.

x1 = x2

Since the force exerted to each spring might be different, let's assume F1 for spring 1 and F2 for spring 2. Hence the equations of spring constant for both springs are

k1 = F1/x -> F1 =k1*x

k2 = F2/x -> F2 =k2*x

While F = F1 + F2

Substitute equation of F1 and F2 into the equation of sum of forces

F = F1 + F2

F = k1*x + k2*x

= x(k1 + k2)

Note that this is applicable because both spring have the same extension of x (I repeat, EXTENTION, not length of the spring)

Considering the general equation of spring forces (Hooke's Law) F = kx,

The effective spring constant for the system is k1 + k2

3 0
3 years ago
A 5kg bag falls a verticle height of 10m before hitting the ground.
g100num [7]

Answer:

u = 7m {s}^{ - 1}

Explanation:

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me(1) = me(2)

where me(1) is mechanical energy while on h=10m

and me(2) is mechanical energy while on the ground

Ek(1) + DynamicE(1) = Ek(2) + DynamicE(2)

Ek(1) is equal to zero since an object that has reached its max height has a speed equal to zero.

DynamicE(2) is equal to zero since it's touching the ground

Using that info we have

m \times g \times h   =   \frac{1}{2}  \times m \times u {}^{2} \\

we divide both sides of the equation with mass to make the math easier.

9.8 \times 10 =  \frac{1}{2}  \times u {}^{2}  \\  \frac{98}{2}  = u {}^{2}  \\ u { }^{2} = 49 \\ u = 7

7 0
4 years ago
PLEASE HELP ME I NEED THIS ASAP!!!!
Zina [86]

Answer:

loud bangs

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3 0
3 years ago
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irinina [24]

Well, that's a nice, concise description, but it applies to a
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5 0
3 years ago
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