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Damm [24]
3 years ago
10

HELP PLEEAAAASSSEEEEEEE What is the definition of net force?

Physics
1 answer:
aleksley [76]3 years ago
8 0

Answer:

the sum of all force being applied to an object.

Explanation:

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I shared a picture of the problem. It’s a basic Physics question and an Algebra question.
julia-pushkina [17]

Hence the expression of ω in terms of m and k is

\omega = \sqrt{\frac{k}{m}

Given the expressions;

T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}

Equating both expressions we will have;

2 \pi \sqrt{\frac{m}{k} }  = \frac{2 \pi}{\omega}

Divide both equations by 2π

\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\

Square both sides

(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}

Take the square root of both sides

\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}

Hence the expression of ω in terms of m and k is

\omega = \sqrt{\frac{k}{m}

3 0
3 years ago
The original meaning of the word "essay' is which of these? treatise dialogue attempt thought
Elina [12.6K]
The answer to this is, attempt.
8 0
4 years ago
Read 2 more answers
The smallest unit of an element that has all of the properties of the element is a/an
AysviL [449]

Answer:B

Explanation: an atom is the smallest particle of an element that can take part in a chemical reaction.

7 0
3 years ago
A toy car has a 1.5 A current, and its resistance is 2 . How much voltage does the car require?
Arisa [49]

Answer:

3 Volts

Explanation:

Using Ohm's Law

         Voltage=current x resistance

              V = I x R

              V = 1.5 x 2

              V = 3 V

6 0
3 years ago
1. Is the collision between the ball and the pendulum elastic or inelastic? Justify your answer by calculating the kinetic energ
Nitella [24]

Answer:

So energy is not conserved and inelastic shock

Explanation:

In the collision between a bullet and a ballistic pendulum, characterized in that the bullet is embedded in the block, if the kinetic energy is conserved the shock is elastic and if it is not inelastic.

Let's find the kinetic energy just before the crash

         K₀ = ½ m vₓ₀²

After the crash we can use the law of conservation of energy

Starting point. Right after the crash, before starting to climb

        Em₀ = K = ½ (m + M) v₂²

Final point. At the maximum height of the pendulum

       Em_{f} = U = (m + M) g h

Where m is the mass of the bullet and M is the mass of the pendulum

        Em₀ = Em_{f}

        ½ (m + M) v₂² = (m + M) g h

        v₂ = √ 2g h

Now we can calculate the final kinetic energy

       K_{f} = ½ (m + M) v₂²²

       K_{f} = ½ (m + M) (2gh)

The relationship between these two kinetic energies is

      K₀ / K_{f} = ½ m vₓ₀² / (½ (m + M) 2 g h)

      K₀ / K_{f} = m / (m + M)  vₓ₀² / 2 g h

We can see that in this relationship the Ko> Kf

So energy is not conserved and inelastic shock

5 0
4 years ago
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