Answer:
An object's acceleration depends on its mass and on the net force acting on it.
Explanation:
Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.
Answer:
Explanation: In DC circuit, the current will flow for a short time, which is required to charge the capacitor. Once you switch it on, it spikes and the gradually decreases to almost zero (0) as the capacitor becomes fully charged.
In an AC circuit, the circuit acts as if the current is flowing throw the plates whereas is not actually flowing. The circuit acts like the AC is flowing through the capacitor.
<u> Ohms law: </u> This law relates voltage difference between two points. Mathematically, the law states that V=IR;
Where
V = voltage difference ; in volts
I = Current ; in Amperes
R = Resistance ; in ohms
<u>1. Answer : </u> given that R = 10 ; V= 12 V ; I = ?
From ohms law, I = V/R
= 12/10
= 1.2 Amp.
<u>2. Answer:</u> given that R = 10 ; V= ? ; I = 5
From ohms law, V = IR
= 10×5 = 50 V
<u>3 . Answer:</u> given that R = ? ; V= 120 ; I = 5
From ohms law, R = V/I
= 120/5
= 24 Ω
<u>4 . Answer:</u> given that R = ? ; V= 10 ; I = 20
From ohms law, R = V/I
= 10/20
= 0.5 Ω
<u>5 . Answer:</u> given that R = 480 ; V= 24 ; I = ?
From ohms law, I = V/R
= 24/480
= 0.05 A
<u>6. Answer:</u> given that R = 150 ; V= ? ; I = 1
From ohms law, V = IR
= 1 × 150
= 150 V
Answer:
In odd nuclei, the left out proton or neutron will contribute to the spin of the nucleus.
Explanation:
The meaning of odd nuclei is atomic mass is odd.
A=odd number.
A=Z+n
Here, Z is proton either it will odd or n will odd which is neutron.
Now according to the shell model the left out proton or neutron will contribute to the spin and parity.
For example,
Take the case of isotope of nitrogen-15.
Here Z is 7, and n is 8 will not contribute in spin.
Now, for Z=7.
![1S^{2} _{\frac{1}{2} }, 1P^{4} _{\frac{3}{2} }, 1P^{1} _{\frac{1}{2} }](https://tex.z-dn.net/?f=1S%5E%7B2%7D%20_%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%2C%201P%5E%7B4%7D%20_%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%2C%201P%5E%7B1%7D%20_%7B%5Cfrac%7B1%7D%7B2%7D%20%7D)
Here,
![j=\frac{1}{2}](https://tex.z-dn.net/?f=j%3D%5Cfrac%7B1%7D%7B2%7D)
and, L=1.
Fort parity,
![(-1)^{L}](https://tex.z-dn.net/?f=%28-1%29%5E%7BL%7D)
Put the value of L.
Parity will be -1.
Now, spin will be
.